After differentiating the last expression we obtain that 1 C(y) = sin 3y. Hence, we get 1 1 sin 3y-cos 2 3 2 where c is equal to y 3/4 A=TT/2 1/2 exact y=π/3 again. c=1/2 A=TT/3 -cos2x = c integrate cos(2x) differentiate sin(2x)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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After differentiating the last expression we obtain that
C(y)
3
= sin 3y.
Hence, we get
-sin 3y
1
Cos 2x = c
where c is equal to
again.
y
3/4
c=1/2
A=Tt/2
integrate
cos(2x)
differentiate
sin(2x)
1/2
exact
A=Tt/3
y=rt/3
Transcribed Image Text:After differentiating the last expression we obtain that C(y) 3 = sin 3y. Hence, we get -sin 3y 1 Cos 2x = c where c is equal to again. y 3/4 c=1/2 A=Tt/2 integrate cos(2x) differentiate sin(2x) 1/2 exact A=Tt/3 y=rt/3
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