After combustion with excess oxygen, a 12.501 g sample of an oil produced 38.196 g of carbon  dioxide and 18.752 g of water. A previous analysis determined that the oil does not contain oxygen.  What is the empirical formula?

Q: Combustion analysis was performed on 1.50 g of a compound containing C, H and N to yield 3.21 g of…

A: Given,  Mass of the compound = 1.50 g  Mass of CO2 = 3.21 g  Mass of H2O = 0.981 g  Empirical…

Q: A 7.73 g sample of an organic compound containing carbon, hydrogen, and oxygen was burned in excess…

A: Given: Compound contains only C, H and O. Mass of compound combusted = 7.73 g. Mass of CO2 produced…

Q: Octanitrocubane is a high energy explosive material composed of the elements C, N, and O. Combustion…

A:

Q: A compound was found to have the following composition by mass: 28.03% Mg, 21.60% Si, 1.16% H, and…

A:

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 13.51 g H2O. Calculate the empirical…

A:

Q: A compound was found to contain 115.49g of Ca, 92.16 g of O, and 5.82 g of H. What is the total mass…

A: mass of Ca = 115.49g mass of O = 92.16 g mass of H =  5.82 g  Molar mass of Ca = 40.078 g/molMolar…

Q: A 2.41 g sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was…

A: Given, mass of 2.41 g sample of a compound produced 1.36 g CO2 and 0.833 g H2O. Moles of…

Q: An ionic compound was formed by combining 8.289 g of copper (Cu) with 1.218 g of nitrogen (N). What…

A: Given that, Mass of copper Cu = 8.289 g Moles of Cu in 8.289 g = 8.289 g/63.546 g/mol = 0.13044 mol…

Q: An elemental analysis of a 0.3285 g of a compound containing C, H, O and S undergo combustion and…

A:

Q: A 50.00 g sample of an organic compound containing only C, H and O is analyzed by combustion…

A: The objective of the question is to determine the empirical formula of the organic compound…

Q: A 1.115-g sample of cobalt was heated with excess sulfur to give 1.722 g of cobalt sulfide. What is…

A: Mass of Co = 1.115 g Mass of S = mass of cobalt sulfide - mass of cobalt                 = 1.722 -…

Q: Combustion analysis of 2.400 g of an unknown compound containing carbon, hydrogen, and oxygen…

A: Solution                       We know that Number of moles = (Given Mass) / (Molecular Mass) Mass…

Q: 4.33 g sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was…

A:

Q: 0.5998 -g sample of a new compound has been analyzed and found to contain the following masses of…

A: The question is based on elemental analysis. we have been given mass of the elements. We have to…

Q: A 2.86 g sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was…

A: Given, mass of 2.86 g sample of a compound produced 1.61 g CO2 and 0.989 g H2O.Moles of CO2 and H2O…

Q: A 57.00g sample is composed of 69.61% Barium, 6.093% Carbon, and 24.28% Oxygen. What is the…

A: Empirical Formula  of the compound is BaCO3

Q: A 20.97 gram sample of cobalt is heated in the presence of excess fluorine. A metal fluoride is…

A:

Q: will

A:

Q: After combustion with excess oxygen, a 12.501 g of a petroleum compound produced 38.196 g of carbon…

A:

Q: A 0.5998-g sample of a new compound has been analyzed and found to contain the following masses of…

A: Given, mass of sample of compound = 0.5998 g The sample contains, mass of Carbon (C) = 0.2322 g mass…

Q: A 0.812 g sample of a compound containing carbon, hydrogen and oxygen was burned in air to produce…

A:

Q: 5.00 g of a compound containing nitrogen and oxygen was decomposed and 1.52 g of nitrogen was…

A: Given: Mass of compound = 5.00 g  Mass of Nitrogen produced=1.52 g  Molar mass of nitrogen = 28…

Q: Combustion of 2.16 g of an unknown compound containing only carbon, hydrogen, and nitrogen produces…

A: To determine the empirical formula , we need to calculate the moles of carbon, hydrogen and nitrogen…

Q: Elemental analysis of a 60.00 g sample of a molecular compound used as a drycleaning fluid finds…

A: A sample of a compound used as a dry cleaning fluid is found to containmass of carbon (C) = 10.80…

Q: A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157 g sample of the…

A:

Q: A 15.00 gram sample of a compound containing carbon, hydrogen, and nitrogen is analyzed by…

A:

Q: A 4.73 mg sample of a compound containing carbon, hydrogen, and oxygen underwent combustion…

A:

Q: A robot spacecraft returned samples from the planetesimal 98765 ALEKS, located in the outer Solar…

A: The data given is,

Q: A given compound is analyzed and found to contain only C, H and O. When a 35.79 g sample of this…

A: Given,

Q: etraphenylporphyrin is a synthetic compound that resembles naturally occurring porphyrins.…

A: Step 1: % by mass of C = 85.96 % % by mass of H = 4.92 % % by mass of N = 100-(85.96 + 4.92)…

Q: Combustion analysis of 2.796 g of an unknown compound containing carbon, hydrogen, and oxygen…

A:

Q: Elemental analysis of an unknown compound shows it to contain 1.314574 g of hydrogen, 13.466853 g of…

A: Molar Mass of Phosphorus = 30.97 g/mol Molar mass of Hydrogen 1.00 g/mol Molar mass of Oxygen = 32…

Q: Combustion of a 1.031-g sample of a compound containing only carbon, hydrogen, and oxygen produced…

A: Empirical formula is the simplest whole number ratio of the compound. Mass of sample = 1.031g Mass…

Q: A 3.09 g sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was…

A: Given- Compound consist of C, H, O, N, and S mass of sample for combustion = 3.09 g mass of CO2 =…

Q: A 21.57 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A: From mole ration of substance reacting together, empirical formula can be found out.

Q: A student used 1.50 g of manganese to react with excess fluorine to form manganese fluoride. If 4.09…

A:

Q: A 2.25 g sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was…

A: Given-Compound consist of C, H, O, N, and Smass of sample for combustion = 2.25 gmass of CO2 = 1.27…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.