After clearing the first column we have the following augmented matrix. 1 45 0 3 3.90 0 12 45 Observe that all the entries in R₂ are multiplies of 3. Dividing all the entries in R₂ the row by this integer will make further row operations much simpler. Determine the row operation that can be applied to do this 1x R₂ Applying this row operation gives the following matrix. <-1 10 0 ✓ 1 45 14 x 45 x 1 2 45

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