After a car accident the skid marks for one car measured 150 feet. Use the formula s = √22d to find the speed of the car before the brakes were applied. S represents speed of the car and d represents length of skid marks. Round your answer to the nearest tenth.

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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After a car accident the skid marks for one car
measured 150 feet. Use the formula s = √22d to find
the speed of the car before the brakes were applied. S
represents speed of the car and d represents length of
skid marks. Round your answer to the nearest tenth.
Transcribed Image Text:After a car accident the skid marks for one car measured 150 feet. Use the formula s = √22d to find the speed of the car before the brakes were applied. S represents speed of the car and d represents length of skid marks. Round your answer to the nearest tenth.
The stopping distance for a car on dry pavement can be measured by the
skid marks on the pavement after an accident. The initial speed of the car, in
miles per hour is related to the length of the skid by the following equation:
s-√22d.
where d is the length of the skid marks in feet for the car to come to a
complete stop, and's is the initial speed of the car.
Answer the following questions based off of the equation above. Show your
work.
1. How fast was a car going if it left skid marks of (130 feet? →→→
S=√226
S=√22-130
S= √2860 53 mph
40=√22d
(40)2=(√220)²
claima: When
the car skids
130 ft the car is
traveling at 53
mph.
2. If a car is traveling at 40 mph, how will the car travel according to the
equation above before it comes to a complete stop.
S = √22d
1600=22d
22
22
73
H
I plugged 130 in
for d and l
multiplied 22
and 130 and
then took the
square root.
chic :
40=√22.13
40=√1606
40 40 ✓
Transcribed Image Text:The stopping distance for a car on dry pavement can be measured by the skid marks on the pavement after an accident. The initial speed of the car, in miles per hour is related to the length of the skid by the following equation: s-√22d. where d is the length of the skid marks in feet for the car to come to a complete stop, and's is the initial speed of the car. Answer the following questions based off of the equation above. Show your work. 1. How fast was a car going if it left skid marks of (130 feet? →→→ S=√226 S=√22-130 S= √2860 53 mph 40=√22d (40)2=(√220)² claima: When the car skids 130 ft the car is traveling at 53 mph. 2. If a car is traveling at 40 mph, how will the car travel according to the equation above before it comes to a complete stop. S = √22d 1600=22d 22 22 73 H I plugged 130 in for d and l multiplied 22 and 130 and then took the square root. chic : 40=√22.13 40=√1606 40 40 ✓
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