AE: GS: PS: m²³_6m² +9m =0 m(m² -com +9)=0 m (m-3)² = 0 M=O (M= 3) (2x) 3x y = a + c₂₂e²³² +₂e² Dy = 36₂e³* + C²₁₂ (3x²²³x + ³x) 3x D³y = 96₂e³x + C₂ y (0)=0 =D₁ (0)=2 D³y (0) = -6 ² + C₂ [(3 ( ³x e ³* + e²x) + 3 e³x] x · D=G+C₂ 2= 30₂ + C₂ 3x D³²y = 96₂ 0²³* + 6630²³² + 903 xe ²³* →→→→-6 = 96₂ +6C3 3x C₁ = = 2 C₂=2 C3₂=-4 3X y = - 2 +2e³x = $xe³x зу
AE: GS: PS: m²³_6m² +9m =0 m(m² -com +9)=0 m (m-3)² = 0 M=O (M= 3) (2x) 3x y = a + c₂₂e²³² +₂e² Dy = 36₂e³* + C²₁₂ (3x²²³x + ³x) 3x D³y = 96₂e³x + C₂ y (0)=0 =D₁ (0)=2 D³y (0) = -6 ² + C₂ [(3 ( ³x e ³* + e²x) + 3 e³x] x · D=G+C₂ 2= 30₂ + C₂ 3x D³²y = 96₂ 0²³* + 6630²³² + 903 xe ²³* →→→→-6 = 96₂ +6C3 3x C₁ = = 2 C₂=2 C3₂=-4 3X y = - 2 +2e³x = $xe³x зу
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Can you please explain how the values of (C1 = -2) , (C2 = 2) , (C3 = -4) where obtained? Thank you.
![AE:
GS:
PS:
m²³³_6m² +9m =0
m(m³-com +9) =0
m (m - 3)² = 0
M-D
(M= 3) (2x)
31
3x
y = a + c₂₂e² + ₂e
Dy = 36₂0²³x + C²₂₂ (3x6³x + ³x)
96₂²³+ C₂ [(3 (³xe³+ ²) + ³e³*]
D³y =
3X
y = - 2 + 20³x
Ủy qể tế tạc, xe-6-4, 6,
+
C₁ = = 2
C₂ = 2
C3=-4
trẻ
y(0)=0
Dy (0)=2
D³y (0) = -6
3x
D=G+C₂
2= 30₂ + C₂
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F26f20fad-e544-4d30-9da3-66767dad5e52%2F23b6b739-3d04-4bc1-b395-80f9d9a207e1%2Fx0r1od_processed.png&w=3840&q=75)
Transcribed Image Text:AE:
GS:
PS:
m²³³_6m² +9m =0
m(m³-com +9) =0
m (m - 3)² = 0
M-D
(M= 3) (2x)
31
3x
y = a + c₂₂e² + ₂e
Dy = 36₂0²³x + C²₂₂ (3x6³x + ³x)
96₂²³+ C₂ [(3 (³xe³+ ²) + ³e³*]
D³y =
3X
y = - 2 + 20³x
Ủy qể tế tạc, xe-6-4, 6,
+
C₁ = = 2
C₂ = 2
C3=-4
trẻ
y(0)=0
Dy (0)=2
D³y (0) = -6
3x
D=G+C₂
2= 30₂ + C₂
=
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