The following 1⁄4 W resistors are in series: 1.2 kΩ, 2.2 kΩ, 3.9 kΩ and 5.6 kΩ What is the maximum voltage that can be applied across the series resistors without exceeding a power rating? Which resistor will burn out first if excessive voltage is applied?
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The following 1⁄4 W resistors are in series: 1.2 kΩ, 2.2 kΩ, 3.9 kΩ and 5.6 kΩ What is the maximum voltage that can be applied across the series resistors without exceeding a power rating? Which resistor will burn out first if excessive voltage is applied?
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- In Fig. , the battery has negligible internal resistance and E = 48.0 V. R1 = R2 = 4.00 Ω and R4 = 3.00 Ω. What must the resistance R3 be for the resistor network to dissipate electrical energy at a rate of 295 W?True or False. As the charge in the capacitor increases, the voltage AV_R across the resistor decreases. Please explain why this is true.Solve the following with THREE quantity of either batteries or resistors. A. Three batteries, each having a voltage of 2.0 V, are connected in series. What is the total voltage across them? CHOICES: 1.5 6 3 2 B. Three resistors, each having a resistance of 30 Ω, are connected in parallel with each other. What is the value of their effective resistance? CHOICES: 10 60 15 30
- The figure represents the charge of 4 RC circuits. Considering that all circuits use a resistor with the same resistance, which one of the five circuits has the capacitor with the smallest capacitance? V V, max Circuit 4 Circuit 3 Circuit 2 Circuit 1 time all 4 circuits have the same C RC circuit 3 has the smallest C RC circuit 4 has the smallest C RC circuit 1 has the smallest C O RC circuit 2 has the smallest C12.0V 750 33Ω 150 99 0 ***The voltage is 12.0 V. Ohms. A. The equivalent resistance of the circuit is B. The current through the 54 Ohms resistor is A. C. The power is dissipated in the 15 Ohms resistor is W. Round all answers to 2 decimal places.An electric circuit consists of six resistors and a real battery with ε = 9.00 V and an internal resistance R = 0.500 Ω a) Find the battery current b) Find voltage across each resistor c) What is the terminal voltage of the battery?
- For the circuit given. What is the charge stored on C3, in mC? The voltage source in the circuit has a potential different of 6 V. C1 = 2.42 mF C2= 4.33 mF C3= 6.96 mFThe figure below shows a battery connected to a circuit. The potential difference across the battery and the resistance of each resistor is given in the figure. 25.0 V 10.5 Ω 10.5 Ω 4.00 Ω 4.00 Ω 20.0 Ω A rectangular circuit begins at its left side at a 25.0 V battery with the positive terminal on top. From the battery, the circuit extends up and to the right to point b. The circuit continues rightward from point b and splits into three parallel vertical branches. The leftmost branch has a resistor labeled 10.5 Ω, the middle branch has a resistor labeled 4.00 Ω and the rightmost branch, from top to bottom, goes through a resistor labeled 4.00 Ω, point c, and a resistor labeled 20.0 Ω. The three branches recombine, the circuit extends to the left passing through point a, bends upward to a resistor labeled 10.5 Ω and reaches the negative terminal of the battery. (a) What is the magnitude of the potential difference (in V) between points a and b in the circuit? (b) What is the…3. vol, tag e vol, tag e 4. Sketch plots of capacitor voltage vs. time for two RC circuits being charged by a battery. Both plots should be at the same scale. a. R = 250 22, C = 1000 μF time b. R = 250 2, C = 10 μF time Calculate the time constant for the R = 250 2, C = 10 uF RC circuit.
- True or False. As the charge in the capacitor increases, the voltage AV_R across the resistor decreases. Please explain why this is true.A capacitor discharges through a 820k2 resistor and drops to its original voltage in 7min How many farads is the capacitor? -t V =VneRC Select one: a. C = 0.72 mF b. c= 0.76 mF C. C= 0.75 mF d. c= 0.74 mFIn the circuit given below, V= 120 V. Find the node voltages y. v2, and v3. 5 k2 50 V 75 V +. v3 6 A 10 k2 The value of vy is V. The value of v2 is V. The value of v3 is V.