(10 Marks) If W = Wo = 20.2 N; angle of Fm with horizontal is 45 degrees (cos(45)=sin(45)=0.7 Locations from the joint center, (where Fj is acting) for Fm = 3 cm; for Wo = 15 cm and for W = 30 cm. Select the best choice for each from (a) to (h) below: (a) Take moments about the joint center to find Fm = N (b) Rotational component of Fm = N (c) Sliding component of Fm = N (see more in the options for (d) to (h) Select one or more: (h) If many muscle are active, we can estimate muscle forces by taking ratios of total muscle lengths (e) Fm can be reduced by making the full arm vertical. (e) Fm can be reduced by making the full arm horizontal. (c) Sliding component of Fm = 212.10 N (d) Fm is large because it is mechanically disadvantaged with little lever arm (d) Fm is large because the person is strong. (g) By making the arm horizontal, the internal and external forces will be aligned. (h) If many muscle are active, we can estimate muscle forces by taking ratios of their cross sectional areas. (f) By making the arm horizontal, external force will have reduced lever arm (a) Fm = 303.00 N (b) Rotational component of Fm = 70.70 N (c) Sliding component of Fm = 282.80 N (a) Fm = 202.00N (b) Rotational component of Fm = 212.10 N (f) By making the arm vertical, external force will have reduced lever arm (g) By making the arm vertical, the internal and external forces will be aligned.

(10 Marks) If W = Wo = 20.2 N; angle of Fm with horizontal is 45 degrees (cos(45)=sin(45)=0.7 Locations from the joint center, (where Fj is acting) for Fm = 3 cm; for Wo = 15 cm and for W = 30 cm. Select the best choice for each from (a) to (h) below: (a) Take moments about the joint center to find Fm = N (b) Rotational component of Fm = N (c) Sliding component of Fm = N (see more in the options for (d) to (h) Select one or more: (h) If many muscle are active, we can estimate muscle forces by taking ratios of total muscle lengths (e) Fm can be reduced by making the full arm vertical. (e) Fm can be reduced by making the full arm horizontal. (c) Sliding component of Fm = 212.10 N (d) Fm is large because it is mechanically disadvantaged with little lever arm (d) Fm is large because the person is strong. (g) By making the arm horizontal, the internal and external forces will be aligned. (h) If many muscle are active, we can estimate muscle forces by taking ratios of their cross sectional areas. (f) By making the arm horizontal, external force will have reduced lever arm (a) Fm = 303.00 N (b) Rotational component of Fm = 70.70 N (c) Sliding component of Fm = 282.80 N (a) Fm = 202.00N (b) Rotational component of Fm = 212.10 N (f) By making the arm vertical, external force will have reduced lever arm (g) By making the arm vertical, the internal and external forces will be aligned.

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