Step 1 By 50 mm Bx Tcose 10 -150 mm 30 min T sino Moment about point B ΣΜ0 P(150mm) = T sin(10)(50mm) T = 17. 28 P Net Force in vertical direction. —Р+ В, — T sin(10°) %3D 0 B, = P+T sin(10°) B, = P+ 17. 28P sin(10°) В, 3D Р+ 3Р B, = 4P Step 2 Net force in horizontal direction, T cos(10°) = B, B = 17.01P Resul tan t reaction at point B B = V(17.01P)² + (4P)² B = 17.47P Now, Shera force shear stress = Area 17.47P A(6 mm /2)2 28 MPa = P = 45. 316 N Force P due to normal stress, 140 = T(3 mm /2) 17.28P 140 = T(3 mm /2)2 P = 57. 27 N The maximum allowable force is P = 45. 316 N
Step 1 By 50 mm Bx Tcose 10 -150 mm 30 min T sino Moment about point B ΣΜ0 P(150mm) = T sin(10)(50mm) T = 17. 28 P Net Force in vertical direction. —Р+ В, — T sin(10°) %3D 0 B, = P+T sin(10°) B, = P+ 17. 28P sin(10°) В, 3D Р+ 3Р B, = 4P Step 2 Net force in horizontal direction, T cos(10°) = B, B = 17.01P Resul tan t reaction at point B B = V(17.01P)² + (4P)² B = 17.47P Now, Shera force shear stress = Area 17.47P A(6 mm /2)2 28 MPa = P = 45. 316 N Force P due to normal stress, 140 = T(3 mm /2) 17.28P 140 = T(3 mm /2)2 P = 57. 27 N The maximum allowable force is P = 45. 316 N
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
How will you verify that the working stress sigma is less than or equal to 28 MPa when P is 57.27 N?
Transcribed Image Text:Step 1
By
50 mm
Bx
Tcose
10
-150 mm
30 min
T sino
Moment about point B
ΣΜ0
P(150mm) = T sin(10)(50mm)
T = 17. 28 P
Net Force in vertical direction.
—Р+ В, — T sin(10°) %3D 0
B, = P+T sin(10°)
B, = P+ 17. 28P sin(10°)
В, 3D Р+ 3Р
B, = 4P
Step 2
Net force in horizontal direction,
T cos(10°) = B,
B = 17.01P
Resul tan t reaction at point B
B = V(17.01P)² + (4P)²
B = 17.47P
Now,
Shera force
shear stress =
Area
17.47P
A(6 mm /2)2
28 MPa =
P = 45. 316 N
Force P due to normal stress,
140 =
T(3 mm /2)
17.28P
140 =
T(3 mm /2)2
P = 57. 27 N
The maximum allowable force is P = 45. 316 N
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you
Structural Analysis (10th Edition)
Civil Engineering
ISBN:
9780134610672
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Principles of Foundation Engineering (MindTap Cou…
Civil Engineering
ISBN:
9781337705028
Author:
Braja M. Das, Nagaratnam Sivakugan
Publisher:
Cengage Learning
Structural Analysis (10th Edition)
Civil Engineering
ISBN:
9780134610672
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Principles of Foundation Engineering (MindTap Cou…
Civil Engineering
ISBN:
9781337705028
Author:
Braja M. Das, Nagaratnam Sivakugan
Publisher:
Cengage Learning
Fundamentals of Structural Analysis
Civil Engineering
ISBN:
9780073398006
Author:
Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel Lanning
Publisher:
McGraw-Hill Education
Traffic and Highway Engineering
Civil Engineering
ISBN:
9781305156241
Author:
Garber, Nicholas J.
Publisher:
Cengage Learning