Consider the mechanical energy of a body at rest on the ground at the Earth's equator, at re = 6400 km Consider the mechanical energy of the same body at rest on the ground at the South pole, at re = 6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator traces a circular path, the object at the Pole does not.) G = 6.67 x 10-11 Nm²kg¯², and the mass of the Earth is M = 5.97 x 1024 kg 1. How much more mechanical energy per kilogram does an object on the ground at the Equator than on the ground at the Pole? 2. E = _ MJ.kg¯. (2 sig figs, do not use scientific notation)

icon
Related questions
Question

9

Consider the mechanical energy of a body at rest on the ground at the Earth's equator, at re = 6400 km
Consider the mechanical energy of the same body at rest on the ground at the South pole, at re = 6400 km. For this problem, we consider the Earth to be spherical.
(Remember, the object at the equator traces a circular path, the object at the Pole does not.)
G = 6.67 x 10-11 Nm²kg¯², and the mass of the Earth is M = 5.97 x 1024 kg
1. How much more mechanical energy per kilogram does an object on the ground at the Equator than on the ground at the Pole?
2. E = _ MJ.kg¯. (2 sig figs, do not use scientific notation)
Transcribed Image Text:Consider the mechanical energy of a body at rest on the ground at the Earth's equator, at re = 6400 km Consider the mechanical energy of the same body at rest on the ground at the South pole, at re = 6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator traces a circular path, the object at the Pole does not.) G = 6.67 x 10-11 Nm²kg¯², and the mass of the Earth is M = 5.97 x 1024 kg 1. How much more mechanical energy per kilogram does an object on the ground at the Equator than on the ground at the Pole? 2. E = _ MJ.kg¯. (2 sig figs, do not use scientific notation)
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer