Infinite uniform line charges of -4 nC/m lie along the (both positive and negative) x and y axes in free space. Find electric field intensity at P (0, 0, 2).
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A: Solution: Given that charge per unit area q1 = 7 z = 4.95 cm charge per unit arrea q2 = -8
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- The dome of a Van de Graaff generator receives a charge of 8.9 x 10-4 C. Find the strength of the electric field in the following situations. (Hint: Review properties of conductors in electrostatic equilibrium. Also, use the points on the surface are outside a spherically symmetric charge distribution; the total charge may be considered to be located at the center of the sphere.) (a) inside the dome N/C (b) at the surface of the dome, assuming it has a radius of 2.8 m N/C (c) 8.3 m from the center of the dome N/CPlease AsapTwo identical thin rods of length L are each charged with a positive charge q that is uniformly distributed on each rod. The rods are arranged parallel to each other along the x direction and are separated by a distance 2d, as shown in the figure below. Determine the electric field at point P, which is located a distance d from the right endpoint of each rod. Hint: You will eventually need the following integral: น 1 S (a²+u²)3/2 du = − + C √a²+u²
- A uniform charge distribution of total charge Q (Q>0) is located along the x-axis. The left end of the charge distribution is located at x=-(144/13)m and its right end is located at x=(25/13)m. Our goal is to calculate the electric field at point P which is located at (x,y)=(0,d). Use letters k for the Coulomb constant, Q for the total charge, d for the y-coordinate of point P, and x and y, for the cartesian coordinates in your responses. (a) Determine the expression for dq. (b) Determine the expression for r2, the magnitude of the vector that is directed from the element of charge dq to the location in which the field is to be determined. (c) Determine the expression for r̂ the unit vector that is directed from the element of charge dq to the location in which the field is to be determined (d) Write the expression for d due to the element of charge dq. (e) Let d=(60/13)m. Integrate the expression to determine the electric field at P. Perform this integration by hand. Avoid using…Consider a charge configuration comprising two point sources, one carrying a positive charge and the other a negative charge. The magnitude of the negative charge is three times as large as the positive charge. Construct a careful sketch of the electric field around the configuration.In the figure a smallI, nonconducting ball of mass m = 0.92 mg and charge q = 2.0 x 108 C (distributed uniformly through its volume) hangs from an insulating thread that makes an angle 0 = 39° with a vertical, uniformly charged nonconducting sheet (shown in cross section). Considering the gravitational force on the ball and assuming the sheet extends far vertically and into and out of the page, calculate the surface charge density o of the sheet. n, 4 ++++ + + tE + +