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6. From Descartes's rule of signs, conclude that the equation x2n – 1 = 0 has 2n – 2 imaginary roots. a %3D 7. Without actually obtaining these roots, show that (a) x+3x+7=0 and (b) x6 – 5x – 7x² + 8x + 20 = 0 - both possess imaginar root

6. From Descartes's rule of signs, conclude that the equation x2n – 1 = 0 has 2n – 2 imaginary roots. a %3D 7. Without actually obtaining these roots, show that (a) x+3x+7=0 and (b) x6 – 5x – 7x² + 8x + 20 = 0 - both possess imaginar root

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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6. From Descartes's rule of signs, conclude that the equation x2n – 1 = 0 has 2n – 2 imaginary roots. a %3D 7. Without actually obtaining these roots, show that (a) x+3x+7=0 and (b) x6 – 5x – 7x² + 8x + 20 = 0 - both possess imaginar root
Transcribed Image Text:6. From Descartes's rule of signs, conclude that the equation x2n – 1 = 0 has 2n – 2 imaginary roots. a %3D 7. Without actually obtaining these roots, show that (a) x+3x+7=0 and (b) x6 – 5x – 7x² + 8x + 20 = 0 - both possess imaginar root
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