The image contains a mathematical derivation with equations involving calculus and exponential functions. 1. The first line of the derivation is: \[ = -\frac{2a^2}{t} \cdot \frac{dS}{dx} \] 2. The next step simplifies to: \[ = -\frac{12a^2 \cdot \frac{dS}{dx}} \] 3. A boxed equation is shown as: \[ S = -\frac{\alpha}{2a^2} S \] 4. The final expression in this segment of the derivation is: \[ S(x) = C e^{-\frac{\alpha^2}{4a^2}} \] The equations appear to be part of a derivation involving differential equations and solving for a function \( S(x) \) in terms of an exponential function. This type of derivation is common in fields involving mathematical physics or engineering, where such functions describe certain physical phenomena.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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I don't understand why (-2a^2)/i=i2a^2. Can you please explain it to. Thank you 

The image contains a mathematical derivation with equations involving calculus and exponential functions.

1. The first line of the derivation is:
   \[
   = -\frac{2a^2}{t} \cdot \frac{dS}{dx}
   \]

2. The next step simplifies to:
   \[
   = -\frac{12a^2 \cdot \frac{dS}{dx}}
   \]

3. A boxed equation is shown as:
   \[
   S = -\frac{\alpha}{2a^2} S
   \]

4. The final expression in this segment of the derivation is:
   \[
   S(x) = C e^{-\frac{\alpha^2}{4a^2}}
   \]

The equations appear to be part of a derivation involving differential equations and solving for a function \( S(x) \) in terms of an exponential function. This type of derivation is common in fields involving mathematical physics or engineering, where such functions describe certain physical phenomena.
Transcribed Image Text:The image contains a mathematical derivation with equations involving calculus and exponential functions. 1. The first line of the derivation is: \[ = -\frac{2a^2}{t} \cdot \frac{dS}{dx} \] 2. The next step simplifies to: \[ = -\frac{12a^2 \cdot \frac{dS}{dx}} \] 3. A boxed equation is shown as: \[ S = -\frac{\alpha}{2a^2} S \] 4. The final expression in this segment of the derivation is: \[ S(x) = C e^{-\frac{\alpha^2}{4a^2}} \] The equations appear to be part of a derivation involving differential equations and solving for a function \( S(x) \) in terms of an exponential function. This type of derivation is common in fields involving mathematical physics or engineering, where such functions describe certain physical phenomena.
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