**Frequency Distribution Analysis** The frequency distribution table displays classes and their corresponding frequencies as follows: | Class | Frequency | |--------|-----------| | 8 – 14 | 8 | | 15 – 21| 7 | | 22 – 28| 7 | | 29 – 35| 3 | | 36 – 42| 6 | | 43 – 49| 7 | To complete parts (a) through (e), perform the following analyses: a) **Determine the total number of observations.** Sum the frequencies to find the total number of observations. b) **Determine the width of each class.** Class width is calculated as the difference between the upper and lower boundaries of any class. For example, for class 8–14, width = 14 - 8 + 1. c) **Determine the midpoint of the second class.** The midpoint is found by averaging the upper and lower boundaries of the class. For 15–21, midpoint = (15 + 21)/2. d) **Determine the modal class (or classes).** The modal class is the class with the highest frequency. e) **Determine the class limits of the next class if an additional class were to be added.** To find the limits of the next class, continue the pattern established by the existing class intervals. **Additional Analysis**: - **Total Observations Calculation**: Add each frequency value: 8 + 7 + 7 + 3 + 6 + 7. - **Class Width Calculation**: An example is provided using the first class (8-14), resulting in a width of 7. - **Explanation of Graph or Diagram**: There is no provided graph or diagram, only the tabular data displayed. Use this distribution to understand how data is spread across different categories or intervals.
**Frequency Distribution Analysis** The frequency distribution table displays classes and their corresponding frequencies as follows: | Class | Frequency | |--------|-----------| | 8 – 14 | 8 | | 15 – 21| 7 | | 22 – 28| 7 | | 29 – 35| 3 | | 36 – 42| 6 | | 43 – 49| 7 | To complete parts (a) through (e), perform the following analyses: a) **Determine the total number of observations.** Sum the frequencies to find the total number of observations. b) **Determine the width of each class.** Class width is calculated as the difference between the upper and lower boundaries of any class. For example, for class 8–14, width = 14 - 8 + 1. c) **Determine the midpoint of the second class.** The midpoint is found by averaging the upper and lower boundaries of the class. For 15–21, midpoint = (15 + 21)/2. d) **Determine the modal class (or classes).** The modal class is the class with the highest frequency. e) **Determine the class limits of the next class if an additional class were to be added.** To find the limits of the next class, continue the pattern established by the existing class intervals. **Additional Analysis**: - **Total Observations Calculation**: Add each frequency value: 8 + 7 + 7 + 3 + 6 + 7. - **Class Width Calculation**: An example is provided using the first class (8-14), resulting in a width of 7. - **Explanation of Graph or Diagram**: There is no provided graph or diagram, only the tabular data displayed. Use this distribution to understand how data is spread across different categories or intervals.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
3: please answer
A, B, C, D
Transcribed Image Text:**Frequency Distribution Analysis**
The frequency distribution table displays classes and their corresponding frequencies as follows:
| Class | Frequency |
|--------|-----------|
| 8 – 14 | 8 |
| 15 – 21| 7 |
| 22 – 28| 7 |
| 29 – 35| 3 |
| 36 – 42| 6 |
| 43 – 49| 7 |
To complete parts (a) through (e), perform the following analyses:
a) **Determine the total number of observations.**
Sum the frequencies to find the total number of observations.
b) **Determine the width of each class.**
Class width is calculated as the difference between the upper and lower boundaries of any class. For example, for class 8–14, width = 14 - 8 + 1.
c) **Determine the midpoint of the second class.**
The midpoint is found by averaging the upper and lower boundaries of the class. For 15–21, midpoint = (15 + 21)/2.
d) **Determine the modal class (or classes).**
The modal class is the class with the highest frequency.
e) **Determine the class limits of the next class if an additional class were to be added.**
To find the limits of the next class, continue the pattern established by the existing class intervals.
**Additional Analysis**:
- **Total Observations Calculation**: Add each frequency value: 8 + 7 + 7 + 3 + 6 + 7.
- **Class Width Calculation**: An example is provided using the first class (8-14), resulting in a width of 7.
- **Explanation of Graph or Diagram**: There is no provided graph or diagram, only the tabular data displayed.
Use this distribution to understand how data is spread across different categories or intervals.
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