Step 3 Now we must multiply both sides of the given equation by the integrating factor e-2x. e-2x/ dy dx -2x dy dx -2y) = e-²x(x² + 3) -2x -2x 2ye = X e + By the choice of the integrating function and the chain rule, the left side of the equation can always be simplified as follows. el P(x) dx dy + P(x)e/P(x) dxy = d [@SP(x) dxy] dx dx Thus, our equation simplifies as the following. -2xy = x²e-2x₁ & [e-2xy] = + dx -2x -2x If the right side of the equation dependent variable. dy dx = f(x, y) can be expressed as a function of the ratio only, then the equation is said to be homogeneous. Such equations can always be transformed into separable equations by a change of the The following method outline can be used for any homogeneous equation. That is, the substitution y = xv(x) transforms a homogeneous equation into a separable equation. The latter equation can be solved by direct integration, and then replacing v by gives the solution to the original equation. X (x² + 3xy + y²) dx - x² dy = 0 (a) Show that the given equation is homogeneous. Dividing by x², we see that the equation becomes (b) Solve the differential equation. |y(x) = = -X log C(x) +1 X X 3y + 2 X )dx-dy. Hence the differential equation is homogeneous.
Step 3 Now we must multiply both sides of the given equation by the integrating factor e-2x. e-2x/ dy dx -2x dy dx -2y) = e-²x(x² + 3) -2x -2x 2ye = X e + By the choice of the integrating function and the chain rule, the left side of the equation can always be simplified as follows. el P(x) dx dy + P(x)e/P(x) dxy = d [@SP(x) dxy] dx dx Thus, our equation simplifies as the following. -2xy = x²e-2x₁ & [e-2xy] = + dx -2x -2x If the right side of the equation dependent variable. dy dx = f(x, y) can be expressed as a function of the ratio only, then the equation is said to be homogeneous. Such equations can always be transformed into separable equations by a change of the The following method outline can be used for any homogeneous equation. That is, the substitution y = xv(x) transforms a homogeneous equation into a separable equation. The latter equation can be solved by direct integration, and then replacing v by gives the solution to the original equation. X (x² + 3xy + y²) dx - x² dy = 0 (a) Show that the given equation is homogeneous. Dividing by x², we see that the equation becomes (b) Solve the differential equation. |y(x) = = -X log C(x) +1 X X 3y + 2 X )dx-dy. Hence the differential equation is homogeneous.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please answer the blank and the wrong answer ty! :D
![Step 3
Now we must multiply both sides of the given equation by the integrating factor e-2x.
e-2x/ dy
dx
-2x dy
dx
-2y) = e-²x(x² + 3)
-2x
-2x
2ye = X e
+
By the choice of the integrating function and the chain rule, the left side of the equation can always be simplified as follows.
el P(x) dx dy + P(x)e/P(x) dxy = d [@SP(x) dxy]
dx
dx
Thus, our equation simplifies as the following.
-2xy = x²e-2x₁
& [e-2xy] =
+
dx
-2x
-2x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb52044d-d588-4d60-8413-960f544d05a0%2F386c4b6a-6179-4c3b-b909-e980998a7362%2Fnhre2iw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Step 3
Now we must multiply both sides of the given equation by the integrating factor e-2x.
e-2x/ dy
dx
-2x dy
dx
-2y) = e-²x(x² + 3)
-2x
-2x
2ye = X e
+
By the choice of the integrating function and the chain rule, the left side of the equation can always be simplified as follows.
el P(x) dx dy + P(x)e/P(x) dxy = d [@SP(x) dxy]
dx
dx
Thus, our equation simplifies as the following.
-2xy = x²e-2x₁
& [e-2xy] =
+
dx
-2x
-2x
![If the right side of the equation
dependent variable.
dy
dx
= f(x, y) can be expressed as a function of the ratio only, then the equation is said to be homogeneous. Such equations can always be transformed into separable equations by a change of the
The following method outline can be used for any homogeneous equation. That is, the substitution y = xv(x) transforms a homogeneous equation into a separable equation. The latter equation can be solved by direct integration, and then
replacing v by gives the solution to the original equation.
X
(x² + 3xy + y²) dx - x² dy = 0
(a) Show that the given equation is homogeneous.
Dividing by x², we see that the equation becomes
(b) Solve the differential equation.
|y(x) =
= -X
log C(x)
+1
X
X
3y + 2
X
)dx-dy. Hence the differential equation is
homogeneous.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb52044d-d588-4d60-8413-960f544d05a0%2F386c4b6a-6179-4c3b-b909-e980998a7362%2Fpsvcsj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If the right side of the equation
dependent variable.
dy
dx
= f(x, y) can be expressed as a function of the ratio only, then the equation is said to be homogeneous. Such equations can always be transformed into separable equations by a change of the
The following method outline can be used for any homogeneous equation. That is, the substitution y = xv(x) transforms a homogeneous equation into a separable equation. The latter equation can be solved by direct integration, and then
replacing v by gives the solution to the original equation.
X
(x² + 3xy + y²) dx - x² dy = 0
(a) Show that the given equation is homogeneous.
Dividing by x², we see that the equation becomes
(b) Solve the differential equation.
|y(x) =
= -X
log C(x)
+1
X
X
3y + 2
X
)dx-dy. Hence the differential equation is
homogeneous.
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