Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 79.5 inches tall. (to 4 decimal places) エ-ド Use the formula Z = where u is the mean, o is the standard deviation, and x is the man's height.

Algebra and Trigonometry (6th Edition)
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Author:Robert F. Blitzer
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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## Calculating the Z-Score

### Problem Statement:
Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 79.5 inches tall. (to 4 decimal places)

### Formula for Z-Score:
\[ Z = \frac{x - \mu}{\sigma} \]

Where:
- \(\mu\) is the mean,
- \(\sigma\) is the standard deviation,
- \(x\) is the man's height.

### Example Calculation:

Given:
- Mean (\(\mu\)) = 69.0 inches
- Standard Deviation (\(\sigma\)) = 2.8 inches
- Man's Height (\(x\)) = 79.5 inches

#### Steps:
1. Subtract the mean from the man's height.
2. Divide the result by the standard deviation.
3. Round the result to four decimal places.

### Detailed Calculation:
1. \( x - \mu = 79.5 - 69.0 = 10.5 \)
2. \( \frac{10.5}{2.8} \approx 3.7500 \)

Thus, the z-score is approximately \( 3.7500 \).

By understanding and applying the above steps, students can calculate the z-score for any given set of data points. This type of calculation is essential for standardizing different measurements and understanding their positions within a normal distribution.
Transcribed Image Text:## Calculating the Z-Score ### Problem Statement: Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 79.5 inches tall. (to 4 decimal places) ### Formula for Z-Score: \[ Z = \frac{x - \mu}{\sigma} \] Where: - \(\mu\) is the mean, - \(\sigma\) is the standard deviation, - \(x\) is the man's height. ### Example Calculation: Given: - Mean (\(\mu\)) = 69.0 inches - Standard Deviation (\(\sigma\)) = 2.8 inches - Man's Height (\(x\)) = 79.5 inches #### Steps: 1. Subtract the mean from the man's height. 2. Divide the result by the standard deviation. 3. Round the result to four decimal places. ### Detailed Calculation: 1. \( x - \mu = 79.5 - 69.0 = 10.5 \) 2. \( \frac{10.5}{2.8} \approx 3.7500 \) Thus, the z-score is approximately \( 3.7500 \). By understanding and applying the above steps, students can calculate the z-score for any given set of data points. This type of calculation is essential for standardizing different measurements and understanding their positions within a normal distribution.
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