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Adjust the bearing sheet and compute the traverse to determine the coordinates of the new points.

Adjust the bearing sheet and compute the traverse to determine the coordinates of the new points.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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2. It is required to provide horizontal control in the area covered by points t1, t12, t3,14, t5 and t6 as shown in Figure 2 below. The extract of the reduced data from the field notebook is as follows: Bearings: A - P = 50° 10' 15", tl – t2 = 84 59' 58", t3 – 12 = 00° 00'16", 14 – 15 = 205° 00' 11", t6 – 15 = 80°00' 15", B- Q = 125° 36' 30" A – tl = 135° 00' 07", t2 – tl = 265° 00’ 00", t3 – 14 = 86 59' 59", t5 – 14 = 25°00' 03", 16 – B = 182° 00' 24", tl – A = 314 59' 52", 12 – 13 = 180° 00' 13", 14 – 13 = 266° 59' 53", t5 – t6 = 259° 59' 59", B – t6 = 02° 00' 24", %3D %3D %3D Distances : A - tl = 69.97 m tl - t2 = 75.52 m To P t2 - t3 = 80.11 m t3 - 14 = 100.18 m 14- t5 = 95.59 m t2 A t5 - t6 = 65.74 m t4 t6 - B = 90.80 m t1 t3 The datum points have the following coordinates: Figure 2 t6 t5 N (m) E A 1000.00 200.00 B 693.50 316.50 B P 1160.10 392.00 To Q 518.80 560.40 Adjust the bearing sheet and compute the traverse to determine the coordinates of the new points.
Transcribed Image Text:2. It is required to provide horizontal control in the area covered by points t1, t12, t3,14, t5 and t6 as shown in Figure 2 below. The extract of the reduced data from the field notebook is as follows: Bearings: A - P = 50° 10' 15", tl – t2 = 84 59' 58", t3 – 12 = 00° 00'16", 14 – 15 = 205° 00' 11", t6 – 15 = 80°00' 15", B- Q = 125° 36' 30" A – tl = 135° 00' 07", t2 – tl = 265° 00’ 00", t3 – 14 = 86 59' 59", t5 – 14 = 25°00' 03", 16 – B = 182° 00' 24", tl – A = 314 59' 52", 12 – 13 = 180° 00' 13", 14 – 13 = 266° 59' 53", t5 – t6 = 259° 59' 59", B – t6 = 02° 00' 24", %3D %3D %3D Distances : A - tl = 69.97 m tl - t2 = 75.52 m To P t2 - t3 = 80.11 m t3 - 14 = 100.18 m 14- t5 = 95.59 m t2 A t5 - t6 = 65.74 m t4 t6 - B = 90.80 m t1 t3 The datum points have the following coordinates: Figure 2 t6 t5 N (m) E A 1000.00 200.00 B 693.50 316.50 B P 1160.10 392.00 To Q 518.80 560.40 Adjust the bearing sheet and compute the traverse to determine the coordinates of the new points.
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