Addition of both Bi3+ and Sn2+ by the method by studying the cathode potential to be made for molding of those in a buffered solution to 0.100 M and pH 1.5. Find the concentration of the more difficult-to-make species or the more easily-reducible species. Sn2+ + 2 e- ↔ Sn (k) E0 = - 0.136 V BiO+ + 2 H+ + 3 e- ↔ Bi (k) E0 = 0.320 V A. 3.2x10-2M B. 2.33 x 10-22M C. 1x10-6M D. 6.2x10-22M
Addition of both Bi3+ and Sn2+ by the method by studying the cathode potential to be made for molding of those in a buffered solution to 0.100 M and pH 1.5. Find the concentration of the more difficult-to-make species or the more easily-reducible species. Sn2+ + 2 e- ↔ Sn (k) E0 = - 0.136 V BiO+ + 2 H+ + 3 e- ↔ Bi (k) E0 = 0.320 V A. 3.2x10-2M B. 2.33 x 10-22M C. 1x10-6M D. 6.2x10-22M
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Addition of both Bi3+ and Sn2+ by the method by studying the cathode potential to be made for molding of those in a buffered solution to 0.100 M and pH 1.5. Find the concentration of the more difficult-to-make species or the more easily-reducible species.
Sn2+ + 2 e- ↔ Sn (k) E0 = - 0.136 V
BiO+ + 2 H+ + 3 e- ↔ Bi (k) E0 = 0.320 V
A. 3.2x10-2M
B. 2.33 x 10-22M
C. 1x10-6M
D. 6.2x10-22M
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