addi $sp, $zero, 6000 # Assume Stack memory starts at 6000. Do not modify. # Procedure Main (Do not modify) Main: add $a0, $zero, $s0 add $a1, $zero, $s1 jal Sum add $s2, $s0, $s1 add $s2, $s2, $v0 j End # Procedure Sum Sum: # Type your code here. # Procedure Dif (Do not modify) Dif: sub $v0, $a1, $a0 jr $ra End:
addi $sp, $zero, 6000 # Assume Stack memory starts at 6000. Do not modify. # Procedure Main (Do not modify) Main: add $a0, $zero, $s0 add $a1, $zero, $s1 jal Sum add $s2, $s0, $s1 add $s2, $s2, $v0 j End # Procedure Sum Sum: # Type your code here. # Procedure Dif (Do not modify) Dif: sub $v0, $a1, $a0 jr $ra End:
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
addi $sp, $zero, 6000 # Assume Stack memory starts at 6000. Do not modify.
# Procedure Main (Do not modify)
Main:
add $a0, $zero, $s0
add $a1, $zero, $s1
jal Sum
add $s2, $s0, $s1
add $s2, $s2, $v0
j End
# Procedure Sum
Sum:
# Type your code here.
# Procedure Dif (Do not modify)
Dif:
sub $v0, $a1, $a0
jr $ra
End:
![Given the following C program and the mapping of registers to variables, complete the MIPS implementation of
procedure Sum.
int Dif(int a, int b) {
return b
a;
}
int Sum(int m, int n) {
int p
Dif(n+1, m-1);
int q
Dif(m+1, n-1);
return p + q;
}
int main() {
int X, У;
Z %3D х + у+ Sum (х, у);
return 0;
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd881417a-8da7-4374-a59b-d48cdce386d5%2F5e799ea5-61f2-4a7a-83ab-4abb64f3f804%2Furtzmyt_processed.png&w=3840&q=75)
Transcribed Image Text:Given the following C program and the mapping of registers to variables, complete the MIPS implementation of
procedure Sum.
int Dif(int a, int b) {
return b
a;
}
int Sum(int m, int n) {
int p
Dif(n+1, m-1);
int q
Dif(m+1, n-1);
return p + q;
}
int main() {
int X, У;
Z %3D х + у+ Sum (х, у);
return 0;
}
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