Add combinations of the following thermochemical equations to determine the enthalphy of the targetreactionReaction 1:CH4(g) + 202(g) → CO2(g)+2H20(1)A H = -890.3 kJ mol1Reaction 2: C2H4(g) + H2(g) →C2H6(g)A H° = -136.3 kJ mol1Reaction 3: 2H2(g) + O2(g) → 2H,0(1)A H° = -571.6 kJ mol1Reaction 4: 2C2H6(g) + 702(g) + 4CO2(g)+6H20(1) A H° = -3120.8 kJ mol1arget reaction: 2CH4(g) C2H4(g)+ 2H2(g)A H° =kJ mol1

Standard enthalpy of test reaction = eqn(1) x 2 - eqn(2) - eqn(4) x 0.5 - eqn(3) x 0.5…

Add combinations of the following thermochemical equations to determine the enthalphy of the target reaction Reaction 1: CH4(g) + 202(g) CO2(g)+2H20(1) AHP = -890.3 kJ mol Reaction 2: C2H4(g) + H2(g) C2H6(g) A H° = -136.3 kJ mol Reaction 3: 2H2() O2(g) 2H20(1) A HO = -571.6 kJ mol1 +] Reaction 4: 2C2H6(g) + 702(g) 4CO2(g)+6H20(1) A H° = -3120.8 kJ mol1 Target reaction: 2CH4(g) C2H4(g)+ 2H2(g) A HO = kJ mol1

Add combinations of the following thermochemical equations to determine the enthalphy of the target reaction Reaction 1: CH4(g) + 202(g) CO2(g)+2H20(1) AHP = -890.3 kJ mol Reaction 2: C2H4(g) + H2(g) C2H6(g) A H° = -136.3 kJ mol Reaction 3: 2H2() O2(g) 2H20(1) A HO = -571.6 kJ mol1 +] Reaction 4: 2C2H6(g) + 702(g) 4CO2(g)+6H20(1) A H° = -3120.8 kJ mol1 Target reaction: 2CH4(g) C2H4(g)+ 2H2(g) A HO = kJ mol1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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