Illustrative Example 1:A teacher from Mabuti Senior High School developed an Online Problem Solving Test to assess the effectivity ofusing online platforms in problem-solving ability of the students. 50 randomly senior high school students need to beselected. In this sample, x= 78 and s = 12. The mean µ and the standard deviation of the population used in thestandardization of the test were 75 and 15, respectively. Use the 95% confidence level to illustrate the rejection region.Solution:3. Determine the The problem does not specify the direction to which thehypothesis will be leading. It means that the test iseritical valuefone-tailed) or Two-Tailed Non-directional.values (twoConfidence Level 98%Critical Values: - +1. 96Stepsllustrationtailed).1. Draw a normaldistributiontesting means.-1.961.964. Shade theregion from thecritical ealuetowards the talof thedistribution2. dentify the test Sincestatistic to be50 is large enough, u- 75 is given, and a- 15is known. (the square of standard devlation isDariance a)Therefore, the test statistic to be used is -test.used.-1.961.96 Activity:Sketch and LocateLocating test statistic:(a) Draw the normal curve.(b) Locate the given test statistic.(c) Determine whether the test statistic will fall on the rejection region or not.Note: Follow the steps in illustrating critical region.1. z= 2, 95% confidence, two-tailed|(a and b)|(c)2. t= -2.34, df = 22, 99% confidence, one-tailed left(a and b)(c)

Each hypothesis has two tail, they are one tail and two tail. Every normal curve has two region,…

Answered: Activity: Sketch and Locate Locating…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Who misses work more often at the ABC Company: Smokers or non-smokers? Are they different? Test at .02 significance level. Smokers: Average number of days absent = 12; standard deviation = 5.0; n = 60Non-Smokers: Average number of days absent = 9; standard deviation = 4.0; n = 40;
The marketing director of a large department store in Metro Manila wants to estimate the average number of customers who enter the store every five minutes. She randomly selects five-minute intervals and counts the number of arrivals at the store. She obtains the figures: 31,37,42,49,52,54,65,68. Find the mean of this sample. [Select] Find the standard deviation of this sample. [Select ] Give the t-value for a 95% confidence coefficient, assuming a normal distribution. [Select] Give a 95% confidence interval for the number of arrivals. [Select] Suppose the computed 95% confidence interval is (39, 60), which of the below interpretation is correct. [Select] >
Objective: Finding critical valuesThe critical value for a 80% confidence inverval for a one sample proportion with a sample size of 27 is 1.28 1.314 1.315 0.84
na test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.4 and a standard deviation of 19.8. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? Omg/dL
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Use the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4321patients treated with the drug, 148 developed the adverse reaction of nausea. Construct a 95% confidence interval for the proportion of adverse reactions. a) Find the best point estimate of the population proportion p. ______________ (Round to three decimal) b. identify the value of the margin of error E E=______________ c. construct the confidence interval _____<p<________ d. write a statement that correctly interprets the confidence interval.
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A sports analytics firm would like to test whether Kyrie Irving’s points per game is different from last season. Last season, he scored 25.2 points per game on average. This season, in a sample of 19 games, his average is 22.9 and the standard deviation is 9.5. Your boss would like you to use �=0.05. What is(are) the critical value(s)? Group of answer choices +1.734 -1.734 -1.960 and +1.960 -2.101 and +2.101 thanks
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Salma claimed that the gas price in Blue Park neighborhood (mean of $3.65) is higher than that in Green Spring (mean of $3.59). She obtained the t-value of 2.223 after calculating data from 6 gas stations in Blue Park and 5 gas stations in Green Spring. Use the chart below and determine if Salma's claim is supported! Table 10-3. Critical values of "t" significance level p= 0.05 significance level p= 0.01 TP 1 12.706 63.657 2 4.303 9.925 3 3.182 5.841 2.776 4.604 5 2.571 4.032 6 2.447 3.707 7 2.365 3.499 2.306 3.355 9 2.262 3.250 10 2.228 3.169 11 2.201 3.106 Copy the following into your text box, fill in the blanks, and answer the questions A. The degree of freedom is: B. The t-calculated value is: and the t-critical value is : C. Comparison: t-calc t-crit (answer with ()) D. Is the null hypothesis accepted or rejected? Explain how you determined that! Also, explain what it means to reject or accept the hypothesis! E. Explain if Salma's claim is supported based on your t-value…
Watching TV: In 2012, the General Social Survey asked a sample of 1318 people how much time they spent watching TV each day. The mean number of hours was 2.95 with a standard deviation of 2.63. A sociologist claims that people watch a mean of 3 hours of TV per day. Do the data provide sufficient evidence to conclude that the mean hours of TV watched per day differs from the claim? Use the a= 0.01 level of significance and the critical value method. Part: 0 / 5 Part 1 of 5 State the appropriate null and alternate hypotheses. H: H₁ : This hypothesis test is a (Choose one) test. 0<0 ☐☐ X □<口 μ 0=0 Ś
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