ACTIVTY 4: SOLVING TIME ONLY NUMBERS1&2 logarithm of a ratio which can be solved by performing the antilogarithm of pH/pKa:10pH-pKa [base]An example of how to use the Henderson-Hasselbalch equation to solve for the pH of a buffer solution is as follows:1.What is the pH of a buffer solution consisting of 0.0350 M NH3 and 0.0500 M NH4+ (Ka for NH4+ is 5.6 x 10-10)?The equation for the reaction is:NH+ H+ + NH3Assuming that the change in concentrations is negligible, in order for the system to reach equilibrium, the Henderson-Hasselbalch equation will be:|NH:%3D['HN0.03501301+vd = HdpH = 9.25 +log ('0.0500%3DpH = 9.095Activity3. True or False!Directions: Write T if the statement is correct and F if otherwise. Write your answer before the number.1. If the buffer is made with a base and its conjugate acid, the pH can be adjusted using a weak acid like HCl.2. A buffer's pH changes greatly when a small amount of strong acid or base is added to it.3. A good buffer mixture should have about equal concentrations of both of its components.4. The strength of a weak acid (buffer) is usually represented as an equilibrium constant.5.The Henderson-Hasselbalch equation connects the measurable value of the pH of a solution with the theoreticalvalue pKa.Activity 4. It's Solving Time!Directions: Solve the following problem. Write your complete solutions.1. What is [H3O'] in a solution of 0.25 M CH3CO2H and 0.030 M NACH3CO2?CH3CO2H(aq)+H2Om=H30°(aq)+CH3CO2 (ag)2. What is [OH] in a solution of 0.125 M CH3NH, and 0.130 M CH3NH3CI?CH3NH2(aq)+H2Ou=CH3NH3 (aq)+OH (aq)K=1.8x105(be)Kp=4.4x10(be)Processing questions:1. Why is understanding of the concept of pH important?2. Why are buffer solutions relevant to life?Page | 5

A buffer solution is formed by the mixing of weak acid with its conjugate base or vice versa. The pH…

Activity 4. It's Solving Time! Directions: Solve the following problem. Write your complete solutions. 1. What is [H3O'] in a solution of 0.25 M CH3CO2H and 0.030 M NaCH3CO2? CH3CO2H(aq)+H2O=H3O°(aq)+CH3CO, (ag) 2. What is [OH] in a solution of 0.125 M CH3NH2 and 0.130 M CH3NH3CI? CH3NH2(aq)+H2Ou CH3NH3 (aq)+OH (aq) K3=1.8x105 K=4.4x10

Activity 4. It's Solving Time! Directions: Solve the following problem. Write your complete solutions. 1. What is [H3O'] in a solution of 0.25 M CH3CO2H and 0.030 M NaCH3CO2? CH3CO2H(aq)+H2O=H3O°(aq)+CH3CO, (ag) 2. What is [OH] in a solution of 0.125 M CH3NH2 and 0.130 M CH3NH3CI? CH3NH2(aq)+H2Ou CH3NH3 (aq)+OH (aq) K3=1.8x105 K=4.4x10

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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