ACTIVITY 3.3: Determining variable valuesA. Solve the expression in C language compiler ,assuming x, z are integer variables:z=x++ +x++where x=7Program codeSample output:B. Solve the following expression :z=++x + y-- - ++y - x-- - x-- -++y - x--where x = 7y= -3Program codeSample output:C. z = x++ +++y - x-- + --ywhere x = 7 andy = 9Program codeSample output:

Answered: ACTIVITY 3.3: Determining variable…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Please help me with this Principles of programming language homework question
translate a c++ program into pep/9 assembly language #include <iostream> using namespace std; int myAge;void ShowVal(int age){ cout << "Age:" << age << endl;} int main() {cout << "Enter age: ";cin >> myAge;ShowVal(myAge);return 0;}
In c++ write VM translator in which it will read a program written in HACK vm from an external file and ultimatley translate each line of code into Hack asm (assembly) , so, Higher level Hack Virtual machine language to Hack level assembly language. For example make it possible to translate the following: One Arithmetic (SUB), one logic (AND), and then Memory access command POP.
please modify the c language program into a pep 9 assembly language #include <stdio.h> int num, answer; int divide ( int numer, int denom ) { int quotient, remain; remain = numer; quotient = 0; while ( remain >= denom ) { remain -= denom; quotient++; } // end for return quotient; } // end of divide( ) int modulus ( int n, int d ) { int quot, rem; rem = n; quot = 0; while ( rem >= d ) { rem -= d; quot++; } // end for return rem; } // end of modulus( ) int main() { printf("? "); scanf("%d", &num); answer = divide(num, 20); printf("%d / 20 = %d\n", num, answer); answer = modulus(num, 20); printf("%d mod 20 = %d\n", num, answer); answer = divide(num, 35); printf("%d / 35 = %d\n", num, answer); answer = modulus(num, 35); printf("%d mod 35 = %d\n", num, answer); return 0; } // end of main

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