ACTIVITY 3.3: Determining variable valuesA. Solve the expression in C language compiler ,assuming x, z are integer variables:z=x++ +x++where x=7Program codeSample output:B. Solve the following expression :z=++x + y-- - ++y - x-- - x-- -++y - x--where x = 7y= -3Program codeSample output:C. z = x++ +++y - x-- + --ywhere x = 7 andy = 9Program codeSample output:

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Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The following question is related to C programming system call Task -5: Write a program in c that the parent process will create one child process and 3 grandchild processes and print their IDs Output: 1. Parent process ID : 0 Child process ID: …. Grand Child process ID: … Grand Child process ID: …. Grand Child process ID: ….
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Note: Write a C Program and format use in the Program (Printf & Scnaf)
3. The two most common type of errors made by programmers are syntax errors and errors in logic. For a simple language such as BASIC the number of such errors is usually small. Let X denote the number of syntax errors and Y the number of errors in logic made on the first run of a BASIC program. Assume that the joint density for (X,Y) is as shown in table 2: x/y 2 3 400 .100 .020 .005 .300 .040 .010 .004 .040 ,010 .009 .003 .009 .008 .007 .003 4. .008 .007 .005 .002 .005 .002 .002 .001 a. Find the probability that a randomly selected program will have neither of these types of error. b. Find the probability that a randomly selected program will contain at least one syntax error and at most one error of logic. c. Find the marginal densities for X and Y d. Find the probability that a randomly selected program contains at least two syntax errors. e. Find the probability that a randomly selected program contains one or two errors in logic.
translate a c++ program into pep/9 assembly language #include <iostream> using namespace std; int myAge;void ShowVal(int age){ cout << "Age:" << age << endl;} int main() {cout << "Enter age: ";cin >> myAge;ShowVal(myAge);return 0;}
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//line 1- //line 2- /line 3 //line 4- //line 5 /line 6 //line 7 //line 8 calculate the average - //line 9 //line 10
The following question supports the attainment of Course Intended Learning Outcomes (CILO): Design computing based solution using control structures, functions, array and other statements. INSTRUCTION: Read and study the assignment below. Solve the problem using C++ programming language, compile, run and screen shot the correct output. Copy and paste the source code or program code and the required sample output (screen shot) in the format below. The output should also display the school name, course name, student name, program, section, date and title of assessment task. PROBLEM: Write a program that will let the user to input year level and status base on table below. The output should be based on the possible combination of year level and status. YEAR LEVEL STATUS OUTPU INPUT OUTPUT INPUT Regular Irregula 1 First Year Rorr Second 2 I o i Year r other 3 Third Year Invalid letters Forth Year 4 other Invalid number Sample Output(1): TECHNOLOGICAL INSTITUTE OF THE PHILIPPINES QUEZON…
please modify the c language program into a pep 9 assembly language #include <stdio.h> int num, answer; int divide ( int numer, int denom ) { int quotient, remain; remain = numer; quotient = 0; while ( remain >= denom ) { remain -= denom; quotient++; } // end for return quotient; } // end of divide( ) int modulus ( int n, int d ) { int quot, rem; rem = n; quot = 0; while ( rem >= d ) { rem -= d; quot++; } // end for return rem; } // end of modulus( ) int main() { printf("? "); scanf("%d", &num); answer = divide(num, 20); printf("%d / 20 = %d\n", num, answer); answer = modulus(num, 20); printf("%d mod 20 = %d\n", num, answer); answer = divide(num, 35); printf("%d / 35 = %d\n", num, answer); answer = modulus(num, 35); printf("%d mod 35 = %d\n", num, answer); return 0; } // end of main

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