Pls answer activity 2 and assessment 1 ACTIVITY 2Directions: Choose the missing statement or reason in the box to complete the two-column form. Work patiently.PETransitive Property of EqualityHP=OESegment Addition Postulate1. Given: HP = OEProve: HO = PEOP=OPHO+OP=OP+PEPROOF:STATEMENTREASONGiven1.2.HP = HO + OP%3DOE = PE + OPAddition Property of Equality3.Reflexive Property of Equality4.5. HO = PE Assessment 1.Directions: Read carefully each item and write the letter of the correct answer on theanswer sheet.1. A Greek mathematician who wrote the core foundation of the axiomatic structureof geometry in his book entitled The Elements.A. Archimedes2. Postulate is also known asB. AristotleC. EuclidD. GalileoA. AxiomB. conjecture3. How many postulates are there that form the basis for all the theorems ofC. proofD. theoremEuclidean Geometry?A. 2B. 5C. 8D. 104. If you extend Lines DE and FG indefinitely towards the direction of the brokenlines, what line does it form?A. intersecting linesB. parallel linesC. perpendicular linesD. straight line5. In Euclidean Geometry, the fifth postulate is also called theA intersecting postulateB. perpendicular postulateC. parallel postulateD. straight line postulate

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Description: Pls answer activity 2 and assessment 1 ACTIVITY 2Directions: Choose the missing statement or reason in the box to complete the two-column form. Work patiently.PETransitive Property of EqualityHP=OESegment Addition Postulate1. Given: HP = OEProve: HO

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ACTIVITY 2 Directions: Choose the missing statement or reason in the box to complete the two column form. Work patiently. Transitive Property of Equality HP=OE Segment Addition Postulate 1. Given: HP = OE Prove: HO = PE OP=OP HO+OP=OP+PE PROOF: STATEMENT REASON 1. Given 2. HP = HO + OP %D OE = PE + OP Addition Property of Equality Reflexive Property of Equality 4. 5. HO = PE 3.

ACTIVITY 2 Directions: Choose the missing statement or reason in the box to complete the two column form. Work patiently. Transitive Property of Equality HP=OE Segment Addition Postulate 1. Given: HP = OE Prove: HO = PE OP=OP HO+OP=OP+PE PROOF: STATEMENT REASON 1. Given 2. HP = HO + OP %D OE = PE + OP Addition Property of Equality Reflexive Property of Equality 4. 5. HO = PE 3.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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