action: ƒ(x.y) = 5xy + y² and Parametric Curve: r(t) = (r², 21) = the parametric curve to covert the function into a parametric function. A s1) = sr? + 21 O s(1) - 10 + 42 3 s() = 1 O s) = s³ - v find the magnitude of the derivative of the parametric curve. ro| = 2
action: ƒ(x.y) = 5xy + y² and Parametric Curve: r(t) = (r², 21) = the parametric curve to covert the function into a parametric function. A s1) = sr? + 21 O s(1) - 10 + 42 3 s() = 1 O s) = s³ - v find the magnitude of the derivative of the parametric curve. ro| = 2
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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We are given a function and a parametric curve
![Function: f(x.y) = 5xy + y? and Parametric Curve: r(1) = (r, 21)
Use the parametric curve to covert the function into a parametric function.
S(1) = sr² + 21
B s(1) = 10 + 41?
%3D
f(1) = 1
S(1) = 51 - 412
Now find the magnitude of the derivative of the parametric curve.
|-6| = 2
412 + 4
100 + 1612
O lr| =
= 21
Now that you have parameterized the function and found the magnitude of the derivative of the parametric curve, you can use
them to find the General Line Integral for this situation.
General Line Imegral = / sFo d and Imteverat: [1. 2]
A Sr |r| di = 46.833
di
dt = 93.666
dt = 180.74](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F70427613-39b9-414c-b7e6-f1c6a3a1890c%2F385b9cce-ed8f-4f22-99db-f0e7104f0913%2Fbg9ejbg_processed.png&w=3840&q=75)
Transcribed Image Text:Function: f(x.y) = 5xy + y? and Parametric Curve: r(1) = (r, 21)
Use the parametric curve to covert the function into a parametric function.
S(1) = sr² + 21
B s(1) = 10 + 41?
%3D
f(1) = 1
S(1) = 51 - 412
Now find the magnitude of the derivative of the parametric curve.
|-6| = 2
412 + 4
100 + 1612
O lr| =
= 21
Now that you have parameterized the function and found the magnitude of the derivative of the parametric curve, you can use
them to find the General Line Integral for this situation.
General Line Imegral = / sFo d and Imteverat: [1. 2]
A Sr |r| di = 46.833
di
dt = 93.666
dt = 180.74
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