Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an El mechanism. The first step is the protonation of the alcohol oxygen to form an oxonium ion. Dehydration of 3-methyl-2-butanol forms one major and two minor organic products. Draw the structures, including hydrogen atoms, of the three organic products of this reaction. H. : OH major product minor product minor product H. H. 3-methyl-2-butanol an oxonium ion Draw the product. Draw minor product 1. Select Rings More Erase Select Draw Rings More Erase Draw H H

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Answer is two minor and one major product 

**Title: Acid-Catalyzed Dehydration of Alcohols**

**Introduction:**
The acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonation of the alcohol oxygen to form an oxonium ion.

**Dehydration Reaction:**

**Reactant:**  
3-methyl-2-butanol

**Reaction Process:**
- The alcohol oxygen is protonated, resulting in the formation of an oxonium ion.
- The oxonium ion undergoes dehydration, leading to the formation of an alkene.

**Products:**
- **Major Product:** The most stable alkene formed.
- **Minor Products:** Two other possible alkenes that are less stable.

**Diagram Explanation:**
- The reaction pathway is shown starting with 3-methyl-2-butanol.
- After protonation, an oxonium ion intermediate is formed.
- This intermediate then forms a major product and two minor products.

**Interactive Section:**
- Two boxes labeled "Draw the major product" and "Draw minor product 1".
- Tools provided for drawing include selection, drawing lines, erasing, and adding carbon/hydrogen atoms.
- The interface provides options to select rings and additional drawing elements.

**Conclusion:**
Understanding the acid-catalyzed dehydration process helps in predicting the major and minor products of alcohol reactions, which is essential in organic synthesis and reaction mechanism studies.
Transcribed Image Text:**Title: Acid-Catalyzed Dehydration of Alcohols** **Introduction:** The acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonation of the alcohol oxygen to form an oxonium ion. **Dehydration Reaction:** **Reactant:** 3-methyl-2-butanol **Reaction Process:** - The alcohol oxygen is protonated, resulting in the formation of an oxonium ion. - The oxonium ion undergoes dehydration, leading to the formation of an alkene. **Products:** - **Major Product:** The most stable alkene formed. - **Minor Products:** Two other possible alkenes that are less stable. **Diagram Explanation:** - The reaction pathway is shown starting with 3-methyl-2-butanol. - After protonation, an oxonium ion intermediate is formed. - This intermediate then forms a major product and two minor products. **Interactive Section:** - Two boxes labeled "Draw the major product" and "Draw minor product 1". - Tools provided for drawing include selection, drawing lines, erasing, and adding carbon/hydrogen atoms. - The interface provides options to select rings and additional drawing elements. **Conclusion:** Understanding the acid-catalyzed dehydration process helps in predicting the major and minor products of alcohol reactions, which is essential in organic synthesis and reaction mechanism studies.
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