Acid Alcohol Ester H;0 Initial amount (25/V) (25/V) Change At Equilibrium + +

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Solve 10 in a chart please like the picture

8:48
l LTE
Gmail
a bartleby.com
SEARCH & ASK
CHAT
VX MATH SOLV
10. At room temperature, the equilibrium constant, Keq is approximately 3. Calculate the number of moles of
reactants and products expected in the equilibrium mixture of this reaction. (Hint: Complete the ICE table
below. Let X be the number of moles of each product fomed at equilibrium. Substitute into the equilibrium
equation using the moles of each reactant and product at equilibrium, each divided by the total reaction
volume. Leave the equilibrium concentrations as fractions. Solve for X. You can then take the square root of
both sides of the equation after cancelling like terms, i.e. the volumes.)
Acid
Alcohol +
Ester
H;0
Initial amount
(25/V)
(25/V)
Change
At Equilibrium
11. What would the % yield of ester be if the reaction were simply allowed to equilibrate (i.e. no productsare
removed)?
12. Compare your experimental % yield of n-propyl propanoate to the predicted equilibrium yield. Were you
successful in driving the reaction to the right?
Transcribed Image Text: 10. At room temperature, the
33
Transcribed Image Text:8:48 l LTE Gmail a bartleby.com SEARCH & ASK CHAT VX MATH SOLV 10. At room temperature, the equilibrium constant, Keq is approximately 3. Calculate the number of moles of reactants and products expected in the equilibrium mixture of this reaction. (Hint: Complete the ICE table below. Let X be the number of moles of each product fomed at equilibrium. Substitute into the equilibrium equation using the moles of each reactant and product at equilibrium, each divided by the total reaction volume. Leave the equilibrium concentrations as fractions. Solve for X. You can then take the square root of both sides of the equation after cancelling like terms, i.e. the volumes.) Acid Alcohol + Ester H;0 Initial amount (25/V) (25/V) Change At Equilibrium 11. What would the % yield of ester be if the reaction were simply allowed to equilibrate (i.e. no productsare removed)? 12. Compare your experimental % yield of n-propyl propanoate to the predicted equilibrium yield. Were you successful in driving the reaction to the right? Transcribed Image Text: 10. At room temperature, the 33
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