Acetic acid partially dissociates according to the reaction below. HC₂H3O2 + H₂O(1) H3O+ + C₂H30₂ ⇒ K = 1.8 x 10-5 @ 25°C Calculate the equilibrium concentrations of the components based on a 0.21 M acetic acid solution. What is the concentration of H3O+? [H3O+] = [?] x 10⁰ M Exponent (yellow) Coefficient (green) Enter

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### Acetic Acid Dissociation Equilibrium

#### Introduction:
Acetic acid partially dissociates in aqueous solution according to the following chemical equilibrium reaction:

\[ \text{HC}_2\text{H}_3\text{O}_2 + \text{H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{C}_2\text{H}_3\text{O}_2^- \]

The equilibrium constant, \( K \), for this reaction is given as \( 1.8 \times 10^{-5} \) at 25°C. 

#### Problem Statement:
Calculate the equilibrium concentrations of the components in the solution based on an initial concentration of 0.21 M acetic acid. Specifically, find the concentration of \( \text{H}_3\text{O}^+ \).

#### Calculation:
Using the given dissociation reaction and equilibrium constant, set up the equilibrium expression:

\[ K = \frac{[\text{H}_3\text{O}^+][\text{C}_2\text{H}_3\text{O}_2^-]}{[\text{HC}_2\text{H}_3\text{O}_2]} \]

Given:
- Initial concentration of acetic acid, \([\text{HC}_2\text{H}_3\text{O}_2]_0 = 0.21 \text{ M} \)
- \[ K = 1.8 \times 10^{-5} \]

Assuming \( x \) is the change in concentration:

\[ [\text{HC}_2\text{H}_3\text{O}_2] = 0.21 - x \]
\[ [\text{H}_3\text{O}^+] = x \]
\[ [\text{C}_2\text{H}_3\text{O}_2^-] = x \]

Substitute these into the equilibrium expression:

\[ 1.8 \times 10^{-5} = \frac{x^2}{0.21 - x} \]

Solve for \( x \) to find the concentration of \( [\text{H}_3\text{O}^+] \).

#### Input:
- Coefficient (green): Enter the coefficient value from the calculated \( [\text{
Transcribed Image Text:### Acetic Acid Dissociation Equilibrium #### Introduction: Acetic acid partially dissociates in aqueous solution according to the following chemical equilibrium reaction: \[ \text{HC}_2\text{H}_3\text{O}_2 + \text{H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{C}_2\text{H}_3\text{O}_2^- \] The equilibrium constant, \( K \), for this reaction is given as \( 1.8 \times 10^{-5} \) at 25°C. #### Problem Statement: Calculate the equilibrium concentrations of the components in the solution based on an initial concentration of 0.21 M acetic acid. Specifically, find the concentration of \( \text{H}_3\text{O}^+ \). #### Calculation: Using the given dissociation reaction and equilibrium constant, set up the equilibrium expression: \[ K = \frac{[\text{H}_3\text{O}^+][\text{C}_2\text{H}_3\text{O}_2^-]}{[\text{HC}_2\text{H}_3\text{O}_2]} \] Given: - Initial concentration of acetic acid, \([\text{HC}_2\text{H}_3\text{O}_2]_0 = 0.21 \text{ M} \) - \[ K = 1.8 \times 10^{-5} \] Assuming \( x \) is the change in concentration: \[ [\text{HC}_2\text{H}_3\text{O}_2] = 0.21 - x \] \[ [\text{H}_3\text{O}^+] = x \] \[ [\text{C}_2\text{H}_3\text{O}_2^-] = x \] Substitute these into the equilibrium expression: \[ 1.8 \times 10^{-5} = \frac{x^2}{0.21 - x} \] Solve for \( x \) to find the concentration of \( [\text{H}_3\text{O}^+] \). #### Input: - Coefficient (green): Enter the coefficient value from the calculated \( [\text{
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