A Ce4+ solution is standardized by titrating it with a 0.1952 M Sn2+ solution. The balanced net ionic equation for the reaction is:2Ce4+(aq) + Sn2+(aq)2Ce3+(aq) + Sn4+(aq)If 21.06 mL of the 0.1952 M Sn2+ solution is required to react completely with 40.00 mL of the Ce4+ solution, calculate the concentration of the Ce4+ solution.

Answered: A Ce4+ solution is standardized by…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A Ce⁴⁺ solution is standardized by titrating it with a 0.1952 M Sn²⁺ solution. The balanced net ionic equation for the reaction is:2Ce⁴⁺(aq)

Sn²⁺(aq)2Ce³⁺(aq)

Sn⁴⁺(aq)
If 21.06 mL of the 0.1952 M Sn²⁺ solution is required to react completely with 40.00 mL of the Ce⁴⁺ solution, calculate the concentration of the Ce⁴⁺ solution.

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Step 1

Answer:

This question is based on stoichiometric calculation where moles of Sn²⁺ will be converted into moles of Ce⁴⁺ using reaction stoichiometry.

Given data:

$C_{S n^{2 +}} = 0.1952 M V_{S n^{2 +}} = 21.06 m L V_{C e^{4 +}} = 40.00 m L$

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