Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![The problem involves an isosceles triangle, \( \triangle CDE \), where sides \( CD \) and \( DE \) are congruent. The expressions for the sides of the triangle are given as follows:
- \( CD = 9x - 25 \)
- \( DE = 6x + 8 \)
- \( CE = 10x - 73 \)
Since \( CD \) is congruent to \( DE \), set the expressions equal to each other to solve for \( x \):
\[ 9x - 25 = 6x + 8 \]
Once the value of \( x \) is found, substitute it back into each expression to find the measure of each side of the triangle.
This task involves algebraic manipulation and understanding of the properties of isosceles triangles.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F06ae4fb8-5de1-4b1b-868d-2962b7df4097%2F928ac721-caa3-4579-bb9c-f784bc52f374%2Fxc9xjwh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The problem involves an isosceles triangle, \( \triangle CDE \), where sides \( CD \) and \( DE \) are congruent. The expressions for the sides of the triangle are given as follows:
- \( CD = 9x - 25 \)
- \( DE = 6x + 8 \)
- \( CE = 10x - 73 \)
Since \( CD \) is congruent to \( DE \), set the expressions equal to each other to solve for \( x \):
\[ 9x - 25 = 6x + 8 \]
Once the value of \( x \) is found, substitute it back into each expression to find the measure of each side of the triangle.
This task involves algebraic manipulation and understanding of the properties of isosceles triangles.
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