Question 3According to the Newton's second law, which of the following is TRUE about a person pushing a lawn mower?The direction of the acceleration is the same direction as that of the force of friction, which is parallel to the ground.The force exerted by the person pushing the mower must be less than the friction opposing the motion.The direction of the acceleration is the same direction as that of the net force, which is parallel to the ground.The net external force applied by the person is the push plus friction exerted on a lawn mower.©2021Illuminate Education TM, Inc.

Answer Newton's second law states that acceleration which a net force on an object produces has a…

Answered: According to the Newton's second law,…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A 3.00-kg object is acted upon by an applied force causing it to move along a rough horizontal plane, with its x 5t² - 1 and y = 3t3 + 2, where x and y are in meters and t is in seconds. The and y coordinates given by x = coefficients of friction between the object and the surface are 0.4 and 0.8. Answer the following questions: a. What are the units of the numerical coefficients? b. Determine the acceleration of the object as a function of time. c. Determine the Net force acting on the object at t = 5s.
A cougar bites a llama of mass m and drags it across some rough horizontal ground. The cougar applies a horizontal force of magnitude F, and the llama is dragged at a constant velocity. The coefficient of kinetic friction is μk. While the cougar applies the force F, the magnitude of the kinetic friction force, fk , on the llama obeys: a)F > µk m g > fk b)F = fk = µk m gc)F = fk < µk m gd)cannot answer, not enough information givene) F > fk = µk m g
A block of mass M is suspended at rest by two strings attached to walls, as shown in the figure. The left string is horizontal with tension force T2 and and the right string with tension force T, makes an angle e with the horizontal. g is the magnitude of the gravitational acceleration. Which of the following statements is true? Select all apply. T2 M O The net force along the y-component is non-zero. O The acceleration along the x-component is zero. O The net force along the x-component is zero. O The acceleration along the y-component is non-zero. O The acceleration along the y-component is zero. O The acceleration along the x-component is non-zero. O The net force along the y-component is zero. O The net force along the x-component is non-zero.
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In the figure here, a box of Cheerios (mass mc = 1.70 kg) and a box of Wheaties (mass mw = 2.60 kg) are accelerated across a horizontal surface by a horizontal force applied to the Cheerios box. The magnitude of the frictional force on the Cheerios box is 2.10 N, and the magnitude of the frictional force on the Wheaties box is 4.60 N. If the magnitude of F is 12.7 N, what is the magnitude of the force on the Wheaties box from the Cheerios box? Number i Unit
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Consider an object at rest on a rough horizontal surface. Which of the following is necessarily correct if we use the model of friction described in the videos and book? The force of friction on the object is smaller than or equal to μg FN, where μs is the coefficient of static friction and FN is the normal force exerted on the object by the surface. The force of friction on the object is proportional to the normal force exerted by the surface on the object. The force of friction on any object opposes motion; since the object is at rest, the force of friction is zero. The force of friction on the object is proportional to the object's weight, i.e. Ff = p.mg, where μs is the coefficient of static friction, m is the mass of the object, and g is acceleration due to Earth's gravity.
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A teenager of mass m1 = 56 kg pushes backwards against the ground with his foot as he rides his skateboard. This exerts a horizontal force of magnitude F foot = = 18.5 N. The skateboard has m2 = 2.6 kg. a. Write an expression for the magnitude of the horizontal component of force that the ground exerts on the teenagers foot, F ground. b. Write an expression in terms to given quantities for the magnitude of the skateboard acceleration, a , while the teenager is pushing backwards on the ground? c. What is the numerical value of the magnitude of the acceleration, a, in m/s square?
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