Question 3According to the Newton's second law, which of the following is TRUE about a person pushing a lawn mower?The direction of the acceleration is the same direction as that of the force of friction, which is parallel to the ground.The force exerted by the person pushing the mower must be less than the friction opposing the motion.The direction of the acceleration is the same direction as that of the net force, which is parallel to the ground.The net external force applied by the person is the push plus friction exerted on a lawn mower.©2021Illuminate Education TM, Inc.

Answer Newton's second law states that acceleration which a net force on an object produces has a…

Answered: According to the Newton's second law,…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Three forces act on particle A located at the origin of an x-y coordinate system. Force B acts at 140o from the positive x-axis, and force C acts at 15o from the positive x-axis. The weight acts down with a magnitude of W = 100 kN. Use the equations of equilibrium to determine the magnitudes of B and C such that particle A is in equilibrium. Using your FBD from problem 1) substitute the known weight and angles α and β into your equations, then solve them simultaneously to find the tensions in cables AC and BC . Fb= 117.92kn Fc= 93.507kn
A block of mass M is suspended at rest by two strings attached to walls, as shown in the figure. The left string is horizontal with tension force T2 and and the right string with tension force T, makes an angle e with the horizontal. g is the magnitude of the gravitational acceleration. Which of the following statements is true? Select all apply. T2 M O The net force along the y-component is non-zero. O The acceleration along the x-component is zero. O The net force along the x-component is zero. O The acceleration along the y-component is non-zero. O The acceleration along the y-component is zero. O The acceleration along the x-component is non-zero. O The net force along the y-component is zero. O The net force along the x-component is non-zero.
A block whose weight is 40 N rests on a horizontal surface. The coefficient of static friction between the block and the surface is 0.50. A string is attached to the block. The string is pulled horizontally with a force of 15 N. Which one of the following statements is correct? O The magnitude of the force of friction on the block is 20 N. O The magnitude of the force of friction on the block is 15 N. O The force of friction cannot be determined because the coefficient of kinetic friction is not given. O The force of friction cannot be determined because the normal force of the surface on the block is not known. O The magnitude of the force of friction on the block is 5 N.
Consider an object at rest on a rough horizontal surface. Which of the following is necessarily correct if we use the model of friction described in the videos and book? The force of friction on the object is smaller than or equal to μg FN, where μs is the coefficient of static friction and FN is the normal force exerted on the object by the surface. The force of friction on the object is proportional to the normal force exerted by the surface on the object. The force of friction on any object opposes motion; since the object is at rest, the force of friction is zero. The force of friction on the object is proportional to the object's weight, i.e. Ff = p.mg, where μs is the coefficient of static friction, m is the mass of the object, and g is acceleration due to Earth's gravity.
A 8 kg decoration hangs from the ceiling. It is suspended by 2 wires. The first wire forms a 40⁰ angle with the ceiling. The second wire forms a 50⁰ angle with the ceiling.a. Find the tension in the 2 wires (including magnitude and direction) b. Assuming the wire that forms the 40⁰ angle with the ceiling has a length of 0.3 metres, how farbelow the ceiling is the decoration suspended?
A man exerts a horizontal force of 131 N on a crate with a mass of 36.2 kg. (a) If the crate doesn't move, what's the magnitude of the static friction force (in N)? Make a free-body diagram and apply the x-component of Newton's second law. N (b) What is the minimum possible value of the coefficient of static friction between the crate and the floor? (Assume the crate remains stationary.) Apply the relationship between static friction and the normal force.
A massive block was pulled at an angle of 30o in a horizontal rough surface by a force of magnitude F enough for the block to move. If we set the +x-axis at the right, which of the following statements is true about the forces acting on the block? Explain answer. A. The direction of the frictional force experienced by the block is to the leftB. The normal force’s direction is 30 degrees above the +x-axisC. The block will not experience friction since F is just enough to move the block D. The direction of the weight of the block is about 210 degrees from the x-axis.
I need the answer as soon as possible
A teenager of mass m1 = 56 kg pushes backwards against the ground with his foot as he rides his skateboard. This exerts a horizontal force of magnitude F foot = = 18.5 N. The skateboard has m2 = 2.6 kg. a. Write an expression for the magnitude of the horizontal component of force that the ground exerts on the teenagers foot, F ground. b. Write an expression in terms to given quantities for the magnitude of the skateboard acceleration, a , while the teenager is pushing backwards on the ground? c. What is the numerical value of the magnitude of the acceleration, a, in m/s square?
Newton's Third Law. A student in elementary physics finds himself in the middle of a large ice rink with a small but finite coefficient of friction between his feet and the ice. He has been taught Newton's Third Law. Since the law says that for every action there is an equal and opposite reaction, all forces add up to zero. Therefore he assumes that there will be no force possible to accelerate him toward the side of the rink and so he must stay at the center. (a) How do you tell him to get to the side?
The correct answer is A. Please show me the steps on how to solve this problem.

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