According to the memory view given below. If RO = 0x20000004, after the LDMIA rO, (r7, r3, r9} instruction is executed, which of the following is the r3 and r0 register contents, respectively (data layout to.g endian)?

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14--> )  According to the memory view given below. If RO = 0x20000004, after the LDMIA rO, (r7, r3, r9} instruction is executed, which of the following is the r3 and r0 register contents, respectively (data layout to.g endian)?

### Memory Layout and Register Initialization Example

#### Explanation

In the image, a memory layout is provided, and a task is given to execute a specific command in the context of register initialization. Here’s the text transcription and analysis of the depicted content.

#### Transcription

"Aşağıda verilen bellek görünümüne göre, R0 = 0x20000004 ise LDMIA r0, {r7, r3, r9} komutu çalıştırıldıktan sonra, r3 ve r0 register içerikleri sırası ile aşağıdakilerden hangisidir (veri yerleşimi big endian)?"

| Memory Address | Memory Content  |
|:--------------:|:---------------:|
| 0x20000013     | 0x79            |
| 0x20000012     | 0xcd            |
| 0x20000011     | 0xa3            |
| 0x20000010     | 0xfd            |
| 0x2000000F     | 0x12            |
| 0x2000000E     | 0x0d            |
| 0x2000000D     | 0xe0            |
| 0x2000000C     | 0xeb            |
| 0x2000000B     | 0x2c            |
| 0x2000000A     | 0x1a            |
| 0x20000009     | 0xdc            |
| 0x20000008     | 0x11            |
| 0x20000007     | 0x34            |
| 0x20000006     | 0xce            |
| 0x20000005     | 0xfd            |
| 0x20000004     | 0xe4            |
| 0x20000003     | 0xa2            |
| 0x20000002     | 0x3f            |
| 0x20000001     | 0x06            |
| 0x20000000     | 0xf5            |

#### Detailed Explanation

- **Problem Context**: 
  Based on the given memory layout, with the starting address stored in register R0 set to 0x20000004, the command `LDMIA r0, {r7, r
Transcribed Image Text:### Memory Layout and Register Initialization Example #### Explanation In the image, a memory layout is provided, and a task is given to execute a specific command in the context of register initialization. Here’s the text transcription and analysis of the depicted content. #### Transcription "Aşağıda verilen bellek görünümüne göre, R0 = 0x20000004 ise LDMIA r0, {r7, r3, r9} komutu çalıştırıldıktan sonra, r3 ve r0 register içerikleri sırası ile aşağıdakilerden hangisidir (veri yerleşimi big endian)?" | Memory Address | Memory Content | |:--------------:|:---------------:| | 0x20000013 | 0x79 | | 0x20000012 | 0xcd | | 0x20000011 | 0xa3 | | 0x20000010 | 0xfd | | 0x2000000F | 0x12 | | 0x2000000E | 0x0d | | 0x2000000D | 0xe0 | | 0x2000000C | 0xeb | | 0x2000000B | 0x2c | | 0x2000000A | 0x1a | | 0x20000009 | 0xdc | | 0x20000008 | 0x11 | | 0x20000007 | 0x34 | | 0x20000006 | 0xce | | 0x20000005 | 0xfd | | 0x20000004 | 0xe4 | | 0x20000003 | 0xa2 | | 0x20000002 | 0x3f | | 0x20000001 | 0x06 | | 0x20000000 | 0xf5 | #### Detailed Explanation - **Problem Context**: Based on the given memory layout, with the starting address stored in register R0 set to 0x20000004, the command `LDMIA r0, {r7, r
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