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According to the Hooke's Law, the force required to stretch a helical spring is
proportional to the distance stretched. The natural length of a given spring is
8cm. A force of 4kg will stretch it to a total length of 10cm. Find the work done in
stretching it from its natural length to a total length of 16 cm. *
4.65 J
7.17 J
O 6.28 J
O 5.32 J

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