According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 2007 were for identity theft. in that year, assume some state had 436 complaints of identity theft out of 1680 consumer complaints. Do these data provide enough evidence to show that that state had a higher proportion of identity theft than 23? Test at the 4 level.

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Chapter1: Starting With Matlab
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According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 2007 were for identity theft. In that year, assume some state had 436 complaints of identity theft out of 1680 consumer complaints. Do these data provide enough evidence to show that that state had a higher proportion of identity theft than 23%? Test at the 4% level.
Transcribed Image Text:According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 2007 were for identity theft. In that year, assume some state had 436 complaints of identity theft out of 1680 consumer complaints. Do these data provide enough evidence to show that that state had a higher proportion of identity theft than 23%? Test at the 4% level.
**T. TEST STATISTIC**

The symbol and value of the random variable on this problem are as follows:

- Leave this answer as a fraction:  
  \[
  \frac{2}{\text{---}}
  \]

The formula set up of the test statistic is as follows:  
(Leave any values that were given as fractions as fractions)

\[
z = \frac{\hat{p} - p}{\sqrt{\frac{p(1-p)}{\text{---}}}}
\]

\[
= \frac{\text{---} - \text{---}}{\sqrt{\left(\frac{\text{---}(1-\text{---})}{\text{---}}\right)}}
\]

**Final answer for the test statistic from technology.**  
- Round to 2 decimal places:  
  \( z = \text{---} \)

**Q. OBTAIN THE P-VALUE**

- Report to 4 decimal places.  
  It is possible when rounded that a p-value is 0.0000.

- P-value = \(\text{---}\)

**M. MAKE A DECISION**

- Since the p-value \(\text{---}\) \(\alpha\), we \(\text{Select an answer}\).

**S. STATE A CONCLUSION**

- There \(\text{Select an answer}\) significant evidence to conclude \(\text{Select an answer}\).
Transcribed Image Text:**T. TEST STATISTIC** The symbol and value of the random variable on this problem are as follows: - Leave this answer as a fraction: \[ \frac{2}{\text{---}} \] The formula set up of the test statistic is as follows: (Leave any values that were given as fractions as fractions) \[ z = \frac{\hat{p} - p}{\sqrt{\frac{p(1-p)}{\text{---}}}} \] \[ = \frac{\text{---} - \text{---}}{\sqrt{\left(\frac{\text{---}(1-\text{---})}{\text{---}}\right)}} \] **Final answer for the test statistic from technology.** - Round to 2 decimal places: \( z = \text{---} \) **Q. OBTAIN THE P-VALUE** - Report to 4 decimal places. It is possible when rounded that a p-value is 0.0000. - P-value = \(\text{---}\) **M. MAKE A DECISION** - Since the p-value \(\text{---}\) \(\alpha\), we \(\text{Select an answer}\). **S. STATE A CONCLUSION** - There \(\text{Select an answer}\) significant evidence to conclude \(\text{Select an answer}\).
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