a)32 B)10.66 NS)48 D)80 TO)5.33 According to the circuit in the figure, how many µC is the charge accumulated on the 20µF capacitor?2µF3µF4µF15 -12µF4µF20V20µF

Answered: According to the circuit in the figure,…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Related questions

Question

10.66

NS)

TO)

5.33

According to the circuit in the figure, how many µC is the charge accumulated on the 20µF capacitor?
2µF
3µF
4µF
15 -
12µF
4µF
20V
20µF

Expert Solution

Step 1

In the above problem, we have to find the total charge accumulated on the $20 μF$ capacitor.

To calculate the charge on the $20 μF$ capacitor first find the equivalent capacitance of the above circuit and then find the voltage across the $20 μF$ capacitor.

Before proceeding to the question, let's have some basics.

If the capacitors are connected in series, the equivalent capacitance is:

$\frac{1}{C_{eq}} = \frac{1}{C_{1}} + \frac{1}{C_{2}} + \frac{1}{C_{3}} + . . . . . . . . \frac{1}{C_{n}}$

If the capacitors are connected in parallel, the equivalent capacitance is:

$C_{eq} = C_{1} + C_{2} + C_{3} + . . . . . . . . . C_{n}$

The relation between Charge(Q), Capacitance(C), and Voltage(V) in a capacitor is:

$Q = CV$

Capacitors connected in series will always have the same amount of charge flowing across them. And capacitors connected in parallel will always have the same amount of voltage across them.