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According to the balanced reaction below, calculate the quantity of moles of NH, gas that form when 4.20 mol of NH, liquid completely reacts: 3 NH (1) - 4 NH,(g)+ N,(g) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 5.60 6.022 x 1023 28.02 3 4.20 1.05 3.37 x 102 17.04 1.40 4 16.8 3.15 12.6 8.43 x 1023 32.06 1 2.53 x 1024 g NH, mol N, g N, mol N,H, g NH mol NH,

According to the balanced reaction below, calculate the quantity of moles of NH, gas that form when 4.20 mol of NH, liquid completely reacts: 3 NH (1) - 4 NH,(g)+ N,(g) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 5.60 6.022 x 1023 28.02 3 4.20 1.05 3.37 x 102 17.04 1.40 4 16.8 3.15 12.6 8.43 x 1023 32.06 1 2.53 x 1024 g NH, mol N, g N, mol N,H, g NH mol NH,

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Reaction Calculation Guide **Objective:** Calculate the quantity of moles of NH₃ gas produced when 4.20 mol of NH₃ liquid completely reacts based on the balanced chemical equation provided. **Chemical Equation:** \[ 3 \text{ NH}_3(\text{l}) \rightarrow 4 \text{ NH}_3(\text{g}) + \text{ N}_2(\text{g}) \] **Instructions:** 1. **Starting Amount:** - Input the starting amount of substance in moles or grams in the designated fields. In this scenario, the starting amount is 4.20 mol of NH₃. 2. **Calculation Method:** - Use the equation to determine the conversion factor needed. In this reaction, for every 3 moles of NH₃(l), 4 moles of NH₃(g) are produced. 3. **Use Multiplier:** - Enter the starting quantity and multiply it by the conversion factor within the parentheses to calculate the desired result. 4. **Add Factor:** - Utilize the provided buttons for multiplication factors and constants, like Avogadro's number \( (6.022 \times 10^{23}) \). 5. **Answer and Reset:** - Display your answer in the designated area. - Use the reset button to clear all inputs and start over. **Interactive Components:** - **Buttons**: Select buttons for specific values or constants: - Numeric values (e.g., 5.60, 3.37 × 10²⁴). - Moles and grams buttons for different substances (e.g., mol NH₃, mol N₂, g NH₃, g N₂). Use this setup to perform stoichiometric calculations and determine the properties of the reactants and products efficiently.
Transcribed Image Text:### Reaction Calculation Guide **Objective:** Calculate the quantity of moles of NH₃ gas produced when 4.20 mol of NH₃ liquid completely reacts based on the balanced chemical equation provided. **Chemical Equation:** \[ 3 \text{ NH}_3(\text{l}) \rightarrow 4 \text{ NH}_3(\text{g}) + \text{ N}_2(\text{g}) \] **Instructions:** 1. **Starting Amount:** - Input the starting amount of substance in moles or grams in the designated fields. In this scenario, the starting amount is 4.20 mol of NH₃. 2. **Calculation Method:** - Use the equation to determine the conversion factor needed. In this reaction, for every 3 moles of NH₃(l), 4 moles of NH₃(g) are produced. 3. **Use Multiplier:** - Enter the starting quantity and multiply it by the conversion factor within the parentheses to calculate the desired result. 4. **Add Factor:** - Utilize the provided buttons for multiplication factors and constants, like Avogadro's number \( (6.022 \times 10^{23}) \). 5. **Answer and Reset:** - Display your answer in the designated area. - Use the reset button to clear all inputs and start over. **Interactive Components:** - **Buttons**: Select buttons for specific values or constants: - Numeric values (e.g., 5.60, 3.37 × 10²⁴). - Moles and grams buttons for different substances (e.g., mol NH₃, mol N₂, g NH₃, g N₂). Use this setup to perform stoichiometric calculations and determine the properties of the reactants and products efficiently.
**Title:** Calculating the Mass of Glucose **Objective:** Determine the mass in grams of \(1.6 \times 10^3\) mol of glucose \((\text{C}_6\text{H}_{12}\text{O}_6)\). **Description and Instructions:** This educational tool is designed to help you calculate the mass of a given amount of glucose in moles using conversion factors. **Components:** 1. **Starting Amount Box:** This is where you input the initial quantity, given as moles of glucose. 2. **Conversion Framework:** - Illustrated as a multiplication equation with slots for inserting values. - Consists of a "Starting Amount" section multiplied by an additional conversion factor within parentheses. 3. **Add Factor Section:** - Buttons provided for various constants and numeric values needed for conversions. - This includes: - Molar mass of glucose (\(180.18 \, \text{g/mol}\)) - Avogadro's number (\(6.022 \times 10^{23}\)) - Other numeric values (e.g., \(84.18\), \(0.29\), \(9.6 \times 10^{20}\), etc.) 4. **Answer Section:** - Displays the calculated result after using the conversion setup. - An option to reset the calculation is available for starting over. 5. **Conversion Factors Available:** - \( \text{molecules C}_6\text{H}_{12}\text{O}_6 \) - \( \text{g C}_6\text{H}_{12}\text{O}_6 \) - \( \text{mol C}_6\text{H}_{12}\text{O}_6/\text{mol} \) **Steps:** 1. Enter or verify the starting amount in moles (given as \(1.6 \times 10^3\) mol). 2. Use the add factor buttons to input necessary conversion factors for calculating grams from moles. 3. Check your answer in the "Answer" section. 4. Use "Reset" to start over if needed. This tool is ideal for educational purposes, helping students understand mole-to-gram conversions for chemical compounds such as glucose.
Transcribed Image Text:**Title:** Calculating the Mass of Glucose **Objective:** Determine the mass in grams of \(1.6 \times 10^3\) mol of glucose \((\text{C}_6\text{H}_{12}\text{O}_6)\). **Description and Instructions:** This educational tool is designed to help you calculate the mass of a given amount of glucose in moles using conversion factors. **Components:** 1. **Starting Amount Box:** This is where you input the initial quantity, given as moles of glucose. 2. **Conversion Framework:** - Illustrated as a multiplication equation with slots for inserting values. - Consists of a "Starting Amount" section multiplied by an additional conversion factor within parentheses. 3. **Add Factor Section:** - Buttons provided for various constants and numeric values needed for conversions. - This includes: - Molar mass of glucose (\(180.18 \, \text{g/mol}\)) - Avogadro's number (\(6.022 \times 10^{23}\)) - Other numeric values (e.g., \(84.18\), \(0.29\), \(9.6 \times 10^{20}\), etc.) 4. **Answer Section:** - Displays the calculated result after using the conversion setup. - An option to reset the calculation is available for starting over. 5. **Conversion Factors Available:** - \( \text{molecules C}_6\text{H}_{12}\text{O}_6 \) - \( \text{g C}_6\text{H}_{12}\text{O}_6 \) - \( \text{mol C}_6\text{H}_{12}\text{O}_6/\text{mol} \) **Steps:** 1. Enter or verify the starting amount in moles (given as \(1.6 \times 10^3\) mol). 2. Use the add factor buttons to input necessary conversion factors for calculating grams from moles. 3. Check your answer in the "Answer" section. 4. Use "Reset" to start over if needed. This tool is ideal for educational purposes, helping students understand mole-to-gram conversions for chemical compounds such as glucose.
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