According to the American Time Use Survey, Americans age 15 and over spend an average of 2.45 hours each day watching television. The distribution of all such amounts of time spent watching television is skewed to the left with a standard deviation of 1.14 hours. Use this information to determine the following two probabilities. Round solutions to four decimal places, if necessary. Find the probability that a single randomly American watches television more than 2.95 hours per day. P(x > 2.95) = %3D Find the probability that the mean time spend watching television per day of a random sample of 59 Americans is more than 2.95 hours. P(a > 2.95) Hint: Notice that the first question refers to a single observation it's a population distribution question (Chapter 6). On the other hand, the second question refers to a sample of size 59, thus it's a sampling distribution of a sample mean exercise (Chapter 7).

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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According to the American Time Use Survey, Americans age 15 and over spend an average of 2.45 hours each day watching television. The distribution of all such amounts of time spent watching television is skewed to the left with a standard deviation of 1.14 hours. Use this information to determine the following two probabilities. Round solutions to four decimal places, if necessary.

Find the probability that a single randomly American watches television more than 2.95 hours per day.

\( P(x > 2.95) = \)

Find the probability that the mean time spent watching television per day of a random sample of 59 Americans is more than 2.95 hours.

\( P(\bar{x} > 2.95) = \)

*Hint:* Notice that the first question refers to a single observation - it's a population distribution question (Chapter 6). On the other hand, the second question refers to a sample of size 59, thus it's a sampling distribution of a sample mean exercise (Chapter 7).
Transcribed Image Text:According to the American Time Use Survey, Americans age 15 and over spend an average of 2.45 hours each day watching television. The distribution of all such amounts of time spent watching television is skewed to the left with a standard deviation of 1.14 hours. Use this information to determine the following two probabilities. Round solutions to four decimal places, if necessary. Find the probability that a single randomly American watches television more than 2.95 hours per day. \( P(x > 2.95) = \) Find the probability that the mean time spent watching television per day of a random sample of 59 Americans is more than 2.95 hours. \( P(\bar{x} > 2.95) = \) *Hint:* Notice that the first question refers to a single observation - it's a population distribution question (Chapter 6). On the other hand, the second question refers to a sample of size 59, thus it's a sampling distribution of a sample mean exercise (Chapter 7).
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