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According to the above four-bar mechanism, the center of gravity of the limb (2) is horizontal locate the vertical linear acceleration components ( ag2x and ag2y) in unit m/s2. (Centers of gravity the midpoints of the bars are)

According to the above four-bar mechanism, the center of gravity of the limb (2) is horizontal locate the vertical linear acceleration components ( ag2x and ag2y) in unit m/s2. (Centers of gravity the midpoints of the bars are)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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a.ag2x = -15,2 & ag2y = -32,6 b.ag2x = -9,3 & ag2y = -34,8 c.aG2x = -20,7 & ag2y = -29,5 d.ag2x = -3,1 & ag2y = -35,9 e.aG2x = -32,6 & ac2y = -15,2 f.ag2x = -35,9 & ag2y = -3,1 g.aG2x = -29,5 & aG2y = -20,7 h.ag2x = -34,8 & aczy = -9,3 i.aG2x = -25,5 & agzy = -25,5 j.a62x = 3,1 & ag2y = -35,9
Transcribed Image Text:a.ag2x = -15,2 & ag2y = -32,6 b.ag2x = -9,3 & ag2y = -34,8 c.aG2x = -20,7 & ag2y = -29,5 d.ag2x = -3,1 & ag2y = -35,9 e.aG2x = -32,6 & ac2y = -15,2 f.ag2x = -35,9 & ag2y = -3,1 g.aG2x = -29,5 & aG2y = -20,7 h.ag2x = -34,8 & aczy = -9,3 i.aG2x = -25,5 & agzy = -25,5 j.a62x = 3,1 & ag2y = -35,9
(3) 3 (4) 04 >X |(1) References: a1 = 160 mm; a2 = 80 mm; a3 = 170 mm; a4 = 120 mm; 02 = 15 degrees, W2= 30 rad / s, 02 = 0 rad/s2 According to the above four-bar mechanism, the center of gravity of the limb (2) is horizontal and locate the vertical linear acceleration components ( ag2x and ag2y) in unit m/s2. (Centers of gravity the midpoints of the bars are)
Transcribed Image Text:(3) 3 (4) 04 >X |(1) References: a1 = 160 mm; a2 = 80 mm; a3 = 170 mm; a4 = 120 mm; 02 = 15 degrees, W2= 30 rad / s, 02 = 0 rad/s2 According to the above four-bar mechanism, the center of gravity of the limb (2) is horizontal and locate the vertical linear acceleration components ( ag2x and ag2y) in unit m/s2. (Centers of gravity the midpoints of the bars are)
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