According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round all answers to 3 places after the decimal point, if necessary.) (a) Compute the probability that a randomly selected peanut M&M is not blue. P(not blue) = (b) Compute the probability that a randomly selected peanut M&M is red or green. P(red or green) = (c) Compute the probability that two randomly selected peanut M&M’s are both yellow. P(both yellow) = (d) If you randomly select six peanut M&M’s, compute that probability that none of them are brown. P(none are brown) = (e) If you randomly select six peanut M&M’s, compute that probability that at least one of them is brown. P(at least one is brown) = (answer each =)
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round all answers to 3 places after the decimal point, if necessary.)
(a) Compute the
P(not blue) =
(b) Compute the probability that a randomly selected peanut M&M is red or green.
P(red or green) =
(c) Compute the probability that two randomly selected peanut M&M’s are both yellow.
P(both yellow) =
(d) If you randomly select six peanut M&M’s, compute that probability that none of them are brown.
P(none are brown) =
(e) If you randomly select six peanut M&M’s, compute that probability that at least one of them is brown.
P(at least one is brown) =
(answer each =)
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