According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. [Round your answers to three decimal places, for example: 0.123] Compute the probability that a randomly selected peanut M&M is not yellow. 0.850 Compute the probability that a randomly selected peanut M&M is orange or blue. 0.460 Compute the probability that two randomly selected peanut M&M's are both blue. 0.529 If you randomly select six peanut M&M's, compute that probability that none of them are green. If you randomly select six peanut M&M's, compute that probability that at least one of them is green.

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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According to Masterfoods, the company that manufactures
M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12%
are red, 23% are blue, 23% are orange and 15% are green.
[Round your answers to three decimal places, for example:
0.123]
Compute the probability that a randomly selected peanut
M&M is not yellow.
0.850
Compute the probability that a randomly selected peanut
M&M is orange or blue.
0.460
Compute the probability that two randomly selected peanut
M&M's are both blue.
0.529
If
you randomly select six peanut M&M's, compute that
probability that none of them are green.
If you randomly select six peanut M&M's, compute that
probability that at least one of them is green.
Submit Question
Transcribed Image Text:According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. [Round your answers to three decimal places, for example: 0.123] Compute the probability that a randomly selected peanut M&M is not yellow. 0.850 Compute the probability that a randomly selected peanut M&M is orange or blue. 0.460 Compute the probability that two randomly selected peanut M&M's are both blue. 0.529 If you randomly select six peanut M&M's, compute that probability that none of them are green. If you randomly select six peanut M&M's, compute that probability that at least one of them is green. Submit Question
Expert Solution
Step 1

You have solved the first two questions correctly, so I'll show the last three questions.

 

c) Given that there are 23% blue M&M's.

So the probability of getting a blue M&M is = 0.23

So the probability of getting 2 blue M&M is= 0.23×0.23=0.05290.053

 

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