According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4

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Hi! I need help finding the probability of selecting two of the same color m&ms, when there’s only a 15% chance of picking one out of 100.
12:597
A myopenmath.com
According to Masterfoods, the company that
manufactures M&M's, 12% of peanut M&M's are brown,
15% are yellow, 12% are red, 23% are blue, 23% are
orange and 15% are green. (Round your answers to 4
decimal places where possible)
a. Compute the probability that a randomly selected
peanut M&M is not orange.
.77
b. Compute the probability that a randomly selected
peanut M&M is blue or red.
.35
c. Compute the probability that two randomly
selected peanut M&M's are both yellow.
0.338
d. If you randomly select four peanut M&M's, compute
that probability that none of them are red.
e. If you randomly select four peanut M&M's, compute
that probability that at least one of them is red.
Submit Question
Transcribed Image Text:12:597 A myopenmath.com According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) a. Compute the probability that a randomly selected peanut M&M is not orange. .77 b. Compute the probability that a randomly selected peanut M&M is blue or red. .35 c. Compute the probability that two randomly selected peanut M&M's are both yellow. 0.338 d. If you randomly select four peanut M&M's, compute that probability that none of them are red. e. If you randomly select four peanut M&M's, compute that probability that at least one of them is red. Submit Question
Expert Solution
Step 1

Given:

p(brown) = 0.12

P(yellow) = 0.15

P(red) = 0.12

P(blue) = 0.23

P(orange) = 0.23

P(green) = 0.15

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