According to kinetic-molecular theory, in which of the following gases will the root-mean-square speed of the molecules be thehighest at 200 °C?ACl2ВSF6Н20None. The molecules of all gases have the same root-mean-square speed at any given temperature.E) HCI

Given that - Temperature = 200°C = 200+273 = 473 K Following gaseous Molecules - Cl2 SF6 H2O HCl The Molecular masses of these Molecules are - Cl2 = 35.5×2 = 71 g/mol SF6 = 32+19×6 = 146 g/mol H2O = 2+16 = 18 g/mol HCl = 1+35.5 = 36.5 g/mol Now, root mean square speed can be written as - urms = √3RT/M Where - urms = root mean square speed R = universal gas constant = 8.314 J/K mol T = temperature = 473 K M = molar mass of the gasNow - (1) Root mean square speed of Cl2 - urms = √ 3×8.314×473/71 = √166.16 = 12.89 ~= 12.9 (2) Root mean square speed of SF6 - urms = √ 3×8.314×473/146 = √80.8 = 8.9888 ~= 9.00 (3) Root mean square speed of H2O - urms = √ 3×8.314×473/18 = √655.42 = 25.6 (4) Root mean square speed of HCl - urms = √ 3×8.314×473/36.5 = √323.22 = 17.978 ~= 18.0 Thus, according to kinetic Molecular theory of gases ,the Highest root mean square speed is of water, H2O at 200°C. Thus, correct option is - C. H2O

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According to kinetic-molecular theory, in which of the following gases will the root-mean-square speed of the molecules be the highest at 200 °C? A CI2 SF6 H2O D) None. The molecules of all gases have the same root-mean-square speed at any given temperature. HCI

According to kinetic-molecular theory, in which of the following gases will the root-mean-square speed of the molecules be the highest at 200 °C? A CI2 SF6 H2O D) None. The molecules of all gases have the same root-mean-square speed at any given temperature. HCI

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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