According to de-Broglie associated associated hypothesis, the with with moving wavelength electron of mass 'm' is 'e. Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is 'Ap'. If the energy (E) of electron and photon is same then relation between '' and '' is
Q: What is continuous weighed sum of de-broglie waves
A: ψ(x,t)=∫φ(px)ei(pxx/ℏ−Et/ℏ)dpxψ(x,t)=∫φ(px)ei(pxx/ℏ−Et/ℏ)dpx
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A: De broglie wavelength of proton = 10 m mass of proton = 1.67 ×10-27 kg
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A: The required wavelength is, ∆E=Ei-Efhcλ=-8 eV--2 eV6.626×10-343×108λ=61.6×10-19λ=2.071×10-7 m
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A: Solution:-Given thatKinetic energy of elctron (KE)=50 keV
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