According to Coulomb’s Law force between two charges is k*q1*q2r2. What will happen if one of the charges is zero? a) No attraction or repulsion b) Always attraction c) Always repulsion d) Cannot predict the nature of the force
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According to Coulomb’s Law force between two charges is k*q1*q2r2. What will happen if one of the charges is zero?
a) No attraction or repulsion
b) Always attraction
c) Always repulsion
d) Cannot predict the nature of the force
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- When point charges q₁ = +2.9 µC and q2 = +2.5 µC are brought near each other, each experiences a repulsive force of magnitude 0.59 N. Determine the distance between the charges. Number 0.2214 eTextbook and Media Units mTwo charges +4 µC and +11 µC are placed along the x axis, with the first charge at the origin (x = 0) and the second charge at x = +1 m. Find the magnitude and direction of the net force on a -9 nC charge when placed at the following locations below. Overall Hint Review Section 5.3 Coulomb's Law. Use Coulomb's Law to calculate force due to each of two charges and add them together for the net force, minding the directions. For part (c), you will need to do the vector sum (more below). a. halfway between the two charges: magnitude of force is direction is Select an answer b. on the x axis at x = -0.5 m: magnitude of force is direction is Select an answer c. at the coordinate (x, y) = (1 m, 0.5 m) (half a meter above the +11 µC charge in a direction perpendicular to the line joining the two fixed charges): Hint for (c) Magnitude of force is degrees below -x axis. mN, and the direction is mN, and the mN, and the2. Three charges are arranged as shown in Figure. Find the magnitude and direction of the electrostatic force on the charge at the origin. [ Given Data Coulomb's constant, Ke = 8.99X10° Nm?/C²] q2 6.00nC 3.00nC 0.250m q1 0.150m -2.00nC q3 1. The electrostatic force F12 calculated (between q2 and q1)from the above diagram is = 2. The electrostatic force F23 calculated (between q2 and q3)from the above diagram is = u N 3. The Magnitude of the resultant force on q2 measured from the above diagram is = μΝ 4. The resultant direction O measured from the -x axis is = degrees
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- SAQ: A charge is placed at the midpoint of the line joining the system of two equal charges +2Q each. The nature and magnitude of the charge that is placed for the equilibrium of the system is a. a) -Q/2 b. b) Q/4 c. c) -Q/4 d. d) none of the above SAQ: Two charges 6 mC, -2 mCare separated by a distance of1 m in air. The distance of the point between the two charges for zero electric potential is a. a) 0.25 m b. b) 0.67 m c. c) 0.75 m13-Two charges +10 μC and +7 μC are placed along the x axis, with the first charge at the origin (x = 0) and the second charge at x = +1 m. Find the magnitude and direction of the net force on a -4 nC charge when placed at the following locations below. Overall Hint Review Section 5.3 Coulomb's Law. Use Coulomb's Law to calculate force due to each of two charges and add them together for the net force, minding the directions. For part (c), you will need to do the vector sum (more below). a. halfway between the two charges: magnitude of force is the direction is (in-x direction b. on the axis at x = -0.5 m: magnitude of force is direction is (in +x directio Hint for (c) c. at the coordinate (x, y) = (1 m, 0.5 m) (half a meter above the +7 μC charge in a direction perpendicular to the line joining the two fixed charges): Magnitude of force is mN, and the direction is mN, and degrees below-x axis. mN, and the