According to an almanac, 80% of adult smokers started smoking before turning 18 years old.(a) Compute the mean and standard deviation of the random variable X, the number of smokers who started smoking before 18 based on a random sample of 300 adults.(b) Interpret the mean.(a) Hx =0x =(Round to the nearest tenth as needed.)(b) What is the correct interpretation of the mean?A. It is expected that in 50% of random samples of 300 adult smokers, 240 will have started smoking before turning 18.B. It is expected that in a random sample of 300 adult smokers, 240 will have started smoking before turning 18.C. It is expected that in a random sample of 300 adult smokers, 240 will have started smoking after turning 18.

Answered: According to an almanac, 80% of adult…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A population of N = 5 scores has a mean of u = 20 and a standard deviation of o = 4. Which of the following is the correct Interpretation of the standard deviation? O The average distance of scores from the mean of p- 20 is 5 points. O The average distance of scores from the mean of u = 20 is 1 point. The average distance of scores from the mean of u = 20 is 4 points. O The average squared distance of scores from the mean of u = 20 is 4 points.
The Intelligence Quotient (IQ) test scores for adults are normally distributed with a population mean of 100 and a population standard deviation of 20. What is the probability we could select a sample of 80 adults and find the mean of this sample is less than 95? 0.0125 0.9750 0.4875 0.9476
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A randomly selected sample of n = 55 individuals over 65 years old takes a test of memorization skills. The sample mean is x = 53, and the standard deviation is s = 6.9. Give the numerical value of the standard error of the mean, s.e. (Round your answer to two decimal places.) s.e.(x) =
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