According to a survey, the average cost of a fast-food meal (quarter-pound cheeseburger, large fries, medium soft drink, excluding taxes) in a certain city is $4.82. Suppose this figure was based on a sample of 27 different establishments and the standard deviation was $0.37. Construct a 95% confidence interval for the population mean cost for all fast-food meals in the city. Assume the costs of a fast-food meal in the city are normally distributed. Using the interval as a guide, is it likely that the population mean is really $4.50? Why or why not? (Round your answers to 4 decimal places, e.g. 1.7589.) Since 4.50 * in the interval, we are 95% confident that u + 4.50. Appendix A Statistical Tables
According to a survey, the average cost of a fast-food meal (quarter-pound cheeseburger, large fries, medium soft drink, excluding taxes) in a certain city is $4.82. Suppose this figure was based on a sample of 27 different establishments and the standard deviation was $0.37. Construct a 95% confidence interval for the population mean cost for all fast-food meals in the city. Assume the costs of a fast-food meal in the city are normally distributed. Using the interval as a guide, is it likely that the population mean is really $4.50? Why or why not? (Round your answers to 4 decimal places, e.g. 1.7589.) Since 4.50 * in the interval, we are 95% confident that u + 4.50. Appendix A Statistical Tables
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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q43
(first arrow option is "is/is not")
second arrow option is "equals/does not equal"
![According to a survey, the average cost of a fast-food meal (quarter-pound cheeseburger, large fries, medium soft drink, excluding taxes) in a certain city is $4.82. Suppose this figure was based on a sample of 27 different establishments and the standard deviation was $0.37. Construct a 95% confidence interval for the population mean cost for all fast-food meals in the city. Assume the costs of a fast-food meal in the city are normally distributed. Using the interval as a guide, is it likely that the population mean is really $4.50? Why or why not?
*(Round your answers to 4 decimal places, e.g., 1.7589.)*
\[ \text{Lower Limit} \leq \mu \leq \text{Upper Limit} \]
Since 4.50 [dropdown menu] in the interval, we are 95% confident that \(\mu\) [dropdown menu] 4.50.
Appendix A Statistical Tables
**Explanation of Diagram:**
- The text features a fill-in-the-blank section for inputting the lower and upper limits of the confidence interval.
- There is a dropdown menu option to complete the statement evaluating whether $4.50 is within the confidence interval.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ff8a9d1-27d7-4c01-984f-c0979e8297f8%2F6e7845af-d550-46d4-ad76-cff2f2f84ac7%2Fhsax6pc_processed.png&w=3840&q=75)
Transcribed Image Text:According to a survey, the average cost of a fast-food meal (quarter-pound cheeseburger, large fries, medium soft drink, excluding taxes) in a certain city is $4.82. Suppose this figure was based on a sample of 27 different establishments and the standard deviation was $0.37. Construct a 95% confidence interval for the population mean cost for all fast-food meals in the city. Assume the costs of a fast-food meal in the city are normally distributed. Using the interval as a guide, is it likely that the population mean is really $4.50? Why or why not?
*(Round your answers to 4 decimal places, e.g., 1.7589.)*
\[ \text{Lower Limit} \leq \mu \leq \text{Upper Limit} \]
Since 4.50 [dropdown menu] in the interval, we are 95% confident that \(\mu\) [dropdown menu] 4.50.
Appendix A Statistical Tables
**Explanation of Diagram:**
- The text features a fill-in-the-blank section for inputting the lower and upper limits of the confidence interval.
- There is a dropdown menu option to complete the statement evaluating whether $4.50 is within the confidence interval.
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