According to a survey in a country. 28% of adults do not own a credit card. Suppose a simple random sample of 400 adults is obtained. (b) What is the probability that in a random sample of 400 adults, more than 32% do not own a credit card? The probability is ___ (Round to four decimal places as needed.)

MATLAB: An Introduction with Applications
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According to a survey in a country. 28% of adults do not own a credit card. Suppose a simple random sample of 400 adults is obtained. (b) What is the probability that in a random sample of 400 adults, more than 32% do not own a credit card? The probability is ___ (Round to four decimal places as needed.)
According to a survey in a country, 28% of adults do not own a credit card. Suppose a simple random sample of 400 adults is obtained. Com
Click here to view the standard normal distribution table (page 1).
Click here to view the standard normal distribution table (page 2).
OB. Approximately normal because n ≤0.05N and np(1-p) < 10
OC. Not normal because n ≤0.05N and np(1-p) ≥ 10
D. Approximately normal because n ≤0.05N and np(1-p) ≥ 10
Determine the mean of the sampling distribution of p.
μ = 0.28 (Round to two decimal places as needed.)
P
Determine the standard deviation of the sampling distribution of p.
OA= 0.022 (Round to three decimal places as needed.).
Р
(b) What is the probability that in a random sample of 400 adults, more than 32% do not own a credit card?
The probability is
(Round to four decimal places as needed.).
v an example
Get more help -
Et
(38)
7₁ 101 √i
1.
More
Clear
64
Transcribed Image Text:According to a survey in a country, 28% of adults do not own a credit card. Suppose a simple random sample of 400 adults is obtained. Com Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). OB. Approximately normal because n ≤0.05N and np(1-p) < 10 OC. Not normal because n ≤0.05N and np(1-p) ≥ 10 D. Approximately normal because n ≤0.05N and np(1-p) ≥ 10 Determine the mean of the sampling distribution of p. μ = 0.28 (Round to two decimal places as needed.) P Determine the standard deviation of the sampling distribution of p. OA= 0.022 (Round to three decimal places as needed.). Р (b) What is the probability that in a random sample of 400 adults, more than 32% do not own a credit card? The probability is (Round to four decimal places as needed.). v an example Get more help - Et (38) 7₁ 101 √i 1. More Clear 64
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