According to a survey in a country, 37% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standardinormaCistribution able page 2) (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal becausens0.05N and np(1 - p) < 10 O B. Approximately normal because ns0.05N and np(1 - p) 2 10 O C. Not normal because ns0.05N and np(1-p) 2 10 O D. Approximately normal because ns0.05N and np(1- p) < 10 Determine the mean of the sampling distribution of p. (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. (Round to three decimal places as needed.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
icon
Related questions
Question
2:a, Need help with a,b,c,d (d)Also would Would it be unusual for a random sample of 600 adults to result in 204 or fewer who do not own a credit​ card? Why?
According to a survey in a country, 37% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below.
Click here to view the standard normal distribution table (page 1).
Click here to view the standard normal distribution able page 2)
(a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below.
O A. Not normal becausens0.05N and np(1 - p)< 10
O B. Approximately normal because ns0.05N and np(1 - p) 2 10
O C. Not normal because ns0.05N and np(1-p) 2 10
O D. Approximately normal because ns0.05N and np(1- p) < 10
Determine the mean of the sampling distribution of p.
(Round to two decimal places as needed.)
Determine the standard deviation of the sampling distribution of p.
(Round to three decimal places as needed.)
Transcribed Image Text:According to a survey in a country, 37% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution able page 2) (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal becausens0.05N and np(1 - p)< 10 O B. Approximately normal because ns0.05N and np(1 - p) 2 10 O C. Not normal because ns0.05N and np(1-p) 2 10 O D. Approximately normal because ns0.05N and np(1- p) < 10 Determine the mean of the sampling distribution of p. (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. (Round to three decimal places as needed.)
(b) What is the probability that in a random sample of 600 adults, more than 39% do not own a credit card?
The probability is
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of 600 adults were obtained, one would expect
to result in more than 39% not owning a credit card.
(Round to the nearest integer as needed.)
(c) What is the probability that in a random sample of 600 adults, between 34% and 39% do not own
credit card?
The probability is.
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of 600 adults were obtained, one would expect
(Round to the nearest integer as needed.)
to result in between 34% and 39% not owning a credit card.
Transcribed Image Text:(b) What is the probability that in a random sample of 600 adults, more than 39% do not own a credit card? The probability is (Round to four decimal places as needed.) Interpret this probability. If 100 different random samples of 600 adults were obtained, one would expect to result in more than 39% not owning a credit card. (Round to the nearest integer as needed.) (c) What is the probability that in a random sample of 600 adults, between 34% and 39% do not own credit card? The probability is. (Round to four decimal places as needed.) Interpret this probability. If 100 different random samples of 600 adults were obtained, one would expect (Round to the nearest integer as needed.) to result in between 34% and 39% not owning a credit card.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 5 steps

Blurred answer
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897…
Glencoe Algebra 1, Student Edition, 9780079039897…
Algebra
ISBN:
9780079039897
Author:
Carter
Publisher:
McGraw Hill
Holt Mcdougal Larson Pre-algebra: Student Edition…
Holt Mcdougal Larson Pre-algebra: Student Edition…
Algebra
ISBN:
9780547587776
Author:
HOLT MCDOUGAL
Publisher:
HOLT MCDOUGAL
College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
Algebra
ISBN:
9781305652231
Author:
R. David Gustafson, Jeff Hughes
Publisher:
Cengage Learning