According to a survey in a country, 19% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p) < 10 O B. Not normal becausens0.05N and np(1 - p) 2 10 O C. Approximately normal because ns0.05N and np(1 - p) < 10 O D. Approximately normal because ns0.05N and np(1 - p) 2 10 Determine the mean of the sampling distribution of p. HA = (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. (Round to three decimal places as needed.)
According to a survey in a country, 19% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p) < 10 O B. Not normal becausens0.05N and np(1 - p) 2 10 O C. Approximately normal because ns0.05N and np(1 - p) < 10 O D. Approximately normal because ns0.05N and np(1 - p) 2 10 Determine the mean of the sampling distribution of p. HA = (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. (Round to three decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![(b) What is the probability that in a random sample of 600 adults, more than 20% do not own a credit card?
The probability is [ ].
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of 600 adults were obtained, one would expect [ ] to result in more than 20% not owning a credit card.
(Round to the nearest integer as needed.)
(c) What is the probability that in a random sample of 600 adults, between 15% and 20% do not own a credit card?
The probability is [ ].
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of 600 adults were obtained, one would expect [ ] to result in between 15% and 20% not owning a credit card.
(Round to the nearest integer as needed.)
(d) Would it be unusual for a random sample of 600 adults to result in 90 or fewer who do not own a credit card? Why? Select the correct choice below and fill in the answer box to complete your choice.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F314336d9-9cd2-4a69-ac2b-dc8a3c81cf54%2F84458659-d53a-4df7-a808-26a3da8bfd4f%2Fbh5ics_processed.png&w=3840&q=75)
Transcribed Image Text:(b) What is the probability that in a random sample of 600 adults, more than 20% do not own a credit card?
The probability is [ ].
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of 600 adults were obtained, one would expect [ ] to result in more than 20% not owning a credit card.
(Round to the nearest integer as needed.)
(c) What is the probability that in a random sample of 600 adults, between 15% and 20% do not own a credit card?
The probability is [ ].
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of 600 adults were obtained, one would expect [ ] to result in between 15% and 20% not owning a credit card.
(Round to the nearest integer as needed.)
(d) Would it be unusual for a random sample of 600 adults to result in 90 or fewer who do not own a credit card? Why? Select the correct choice below and fill in the answer box to complete your choice.
![According to a survey in a country, 19% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below.
(a) Describe the sampling distribution of \(\widehat{p}\), the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of \(\widehat{p}\) below.
- A. Not normal because \(n \leq 0.05N\) and \(np(1-p) < 10\)
- B. Not normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\)
- C. Approximately normal because \(n \leq 0.05N\) and \(np(1-p) < 10\)
- D. Approximately normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\)
Determine the mean of the sampling distribution of \(\widehat{p}\).
\[\mu_{\widehat{p}} = \,\] [Round to two decimal places as needed.]
Determine the standard deviation of the sampling distribution of \(\widehat{p}\).
\[\sigma_{\widehat{p}} = \,\] [Round to three decimal places as needed.]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F314336d9-9cd2-4a69-ac2b-dc8a3c81cf54%2F84458659-d53a-4df7-a808-26a3da8bfd4f%2Fb7ha09_processed.png&w=3840&q=75)
Transcribed Image Text:According to a survey in a country, 19% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below.
(a) Describe the sampling distribution of \(\widehat{p}\), the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of \(\widehat{p}\) below.
- A. Not normal because \(n \leq 0.05N\) and \(np(1-p) < 10\)
- B. Not normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\)
- C. Approximately normal because \(n \leq 0.05N\) and \(np(1-p) < 10\)
- D. Approximately normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\)
Determine the mean of the sampling distribution of \(\widehat{p}\).
\[\mu_{\widehat{p}} = \,\] [Round to two decimal places as needed.]
Determine the standard deviation of the sampling distribution of \(\widehat{p}\).
\[\sigma_{\widehat{p}} = \,\] [Round to three decimal places as needed.]
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