25- (b) What is the probability that in a random sample of 600 adults, more than 20% do not own a credit card?The probability is [ ]. (Round to four decimal places as needed.)Interpret this probability.If 100 different random samples of 600 adults were obtained, one would expect [ ] to result in more than 20% not owning a credit card. (Round to the nearest integer as needed.)(c) What is the probability that in a random sample of 600 adults, between 15% and 20% do not own a credit card?The probability is [ ]. (Round to four decimal places as needed.)Interpret this probability.If 100 different random samples of 600 adults were obtained, one would expect [ ] to result in between 15% and 20% not owning a credit card. (Round to the nearest integer as needed.)(d) Would it be unusual for a random sample of 600 adults to result in 90 or fewer who do not own a credit card? Why? Select the correct choice below and fill in the answer box to complete your choice. According to a survey in a country, 19% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below.(a) Describe the sampling distribution of \(\widehat{p}\), the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of \(\widehat{p}\) below.- A. Not normal because \(n \leq 0.05N\) and \(np(1-p) < 10\)- B. Not normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\)- C. Approximately normal because \(n \leq 0.05N\) and \(np(1-p) < 10\)- D. Approximately normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\)Determine the mean of the sampling distribution of \(\widehat{p}\).\[\mu_{\widehat{p}} = \,\] [Round to two decimal places as needed.]Determine the standard deviation of the sampling distribution of \(\widehat{p}\).\[\sigma_{\widehat{p}} = \,\] [Round to three decimal places as needed.]

Dear student as per guidelines we answer the first three subparts only.

According to a survey in a country, 19% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p) < 10 O B. Not normal becausens0.05N and np(1 - p) 2 10 O C. Approximately normal because ns0.05N and np(1 - p) < 10 O D. Approximately normal because ns0.05N and np(1 - p) 2 10 Determine the mean of the sampling distribution of p. HA = (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. (Round to three decimal places as needed.)

According to a survey in a country, 19% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p) < 10 O B. Not normal becausens0.05N and np(1 - p) 2 10 O C. Approximately normal because ns0.05N and np(1 - p) < 10 O D. Approximately normal because ns0.05N and np(1 - p) 2 10 Determine the mean of the sampling distribution of p. HA = (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. (Round to three decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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