According to a study of political prisoners, the mean duration of imprisonment for 34 prisoners withchronic post-traumatic stress disorder (PTSD) was 34.4 months. Assuming that o=37 months, determine a 95%confidence interval for the mean duration of imprisonment, μ, of all political prisoners with chronic PTSD. Interpretyour answer in words.Click here to view Page 1 of the table of areas under the standard normal curve.Click here to view Page 2 of the table of areas under the standard normal curve.A 95% confidence interval for the population mean is from(Round to one decimal place as needed.)months tomonths.

Sample size n=34 Sample mean x¯=34.4 Population standard deviation σ=37 Confidence level is 95%…

Answered: According to a study of political…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An agriculture researcher plants twenty five plots with a new variety of corn. The average yielded for these plots is x-bar = 150 bushels per acre. Assume that the yield per acre for the new variety of corn follows a normal distribution with unknown mean and standard deviation = 10 bushels per acre. A 90% Confidence interval for mean is?
Scores on a standardized exam are known to follow a normal distribution. A researcher estimates that the mean score of the exam to be between 151.85 and 154.15, with a 98% confidence interval. What is the margin of error?
What is the relationship between a person's income and their level of education, and how can this be measured using statistical methods?
In a test of effectiveness of garlic for lowering cholesterol, 44 subjects were treated with garli in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes in their levels of LDL cholesterol (inmg/dL) have a mean of 3.9 and a standard deviation of 15.6. What is the best point estimate of the population mean net change in LDL cholesterol after the garlic treatment? The best point estimate is mg/dl? Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? What is the confidence interval estimate of the population mean u?
What percent of cases fall more than 1.5 standard deviations away from the mean?
Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women
According to the Statistical Abstract of the United States, the mean family size in 2010 was 3.14 persons. Suppose a random sample of 225 families taken this year yields a sample mean size of 3.05 persons, and suppose we assume the population standard deviation of family sizes is o = 1 person. Using a 5% significance level, test the hypothesis that the mean family size has decreased since 2010. Perform your hypothesis test, and select the best interpretation of your results from the choices below. Select one: O a. At the 5% level of significance the data are statistically significant. We cannot determine the average family size has decreased since 2010. O b. At the 5% level of significance the data are statisticall significant. We can determine the average family size has decreased since 2010. O c. At the 5% level of significance the data is not statistically significant. We cannot conclude the average family size has decreased since 2010. O d. At the 5% level of significance the data…
Low‑density lipoprotein, or LDL, is the main source of cholesterol buildup and blockage in the arteries. This is why LDL is known as "bad cholesterol." LDL is measured in milligrams per deciliter of blood, or mg/dL. In a population of adults at risk for cardiovascular problems, the distribution of LDL levels is normal, with a mean of 123123 mg/dL and a standard deviation of 4141 mg/dL. If an individual's LDL is at least 11 standard deviation or more above the mean, he or she will be monitored carefully by a doctor. What percentage of individuals from this population will have LDL levels 11 or more standard deviations above the mean? Use the 6868–9595–99.799.7 rule. (Enter your exact answer as a whole number.)
In 16 women with diabetes, the morning blood sugar mean was 49.4 with a standard deviation of 24.0. In normal healthy women, the mean was 47.0. From the sample information, can we conclude that the blood sugar mean in women with rheumatoid arthritis is greater than that in normal women? Assume a significance level of 0.05.
I have a question: You are interested in estimating the the mean weight of the local adult population of female white-tailed deer (doe). From past data, you estimate that the standard deviation of all adult female white-tailed deer in this region to be 21 pounds. What sample size would you need to in order to estimate the mean weight of all female white-tailed deer, with a 94% confidence level, to within 4 pounds of the actual weight?
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