According to a recent report (based on historical data), 47% of college student internships are unpaid. A recent survey of 100 college interns at a local university found that 59 had unpaid internships. Follow the five-step p-value approach to hypothesis testing (see Chapter 9 Powerpoint slides #53 - 59 or e-text p. 339 - 340. Use a 0.10 level of significance to determine whether the proportion of college interns that had unpaid internships is different from 0.47. Part 1
According to a recent report (based on historical data), 47% of college student internships are unpaid. A recent survey of 100 college interns at a local university found that 59 had unpaid internships. Follow the five-step p-value approach to hypothesis testing (see Chapter 9 Powerpoint slides #53 - 59 or e-text p. 339 - 340. Use a 0.10 level of significance to determine whether the proportion of college interns that had unpaid internships is different from 0.47. Part 1
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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According to a recent report (based on historical data), 47% of college student internships are
unpaid. A recent survey of 100 college interns at a local university found that 59 had unpaid internships.
Follow the five-step p-value approach to hypothesis testing (see Chapter 9 Powerpoint slides #53 - 59 or e-text p. 339 - 340. Use a 0.10 level of significance to determine whether the proportion of college interns that had unpaid internships is different from 0.47.
Part 1
Let π be the population proportion. Determine the null hypothesis, H0, and the alternative hypothesis, H1.
(Type integers or decimals. Do not round.)
(Type integers or decimals. Do not round.)
A. H0 : μ = 0.47; H1 : μ ≠ 0.47 , because μ is always used in hypothesis testing
B. H0 : π = 0.47; H1 : π ≠ 0.47, because the two hypotheses always use a known or likely to be true value for the population proportion
C. H0 : π = 0.59; H1 : π ≠ 0.59, since we are trying to prove the sample proportion of 59100= 0.59
is really true
D. H0 : π ≠ 0.47; H1 : π = 0.47, since H0must never have an equal symbol
What is the test statistic? (Round to two decimal places to the right of the decimal point as needed.)
A. ZSTAT =(0.47 − 0.59)(0.59)•(1−0.59)100 = −2.44, using formula (9.3)
B. tSTAT =(0.59 − 0.47)0.47100 = +2.55, using formula (9.2) since the sample standard deviation is not known
C. ZSTAT =(0.59 − 0.47)(0.47)•(1−0.47)100 = +2.40, using formula (9.3)
D. ZSTAT =(0.59 − 0.47)(0.59)•(1−0.47)100 = +2.15, using formula (9.3)
What is the p-value? (Round to three decimal places to the right of the decimal point as needed.)
A. p-value = NORM.S.DIST(2.40,1) = 0.992
B. p-value = 2*(1-NORM.S.DIST(2.40,1) = 0.016
C. p-value = 2*NORM.S.DIST(2.40,1) = 1.984
D. p-value = 1-NORM.S.DIST(2.40,1)
What is the final conclusion?
A. Do not reject the null hypothesis. There is sufficient evidence that the proportion of college interns that had unpaid interships is different from 0.47 because the p-value is less than level of significance.
B. Do not reject the null hypothesis. There is not enough evidence that the proportion of college interns that had unpaid interships is different from 0.47 because the p-value is greater than level of significance.
C. Reject the null hypothesis. There is sufficient evidence that the proportion of college interns that had unpaid interships is different from 0.47 because the p-value is less than level of significance.
D. Reject the null hypothesis. There is enough evidence to show that the proportion of college interns that had unpaid interships is different from 0.47 because the p-value is greater than level of significance.
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